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nikitadnepr [17]
3 years ago
13

Plz help me I been on these for like an hour

Mathematics
2 answers:
7nadin3 [17]3 years ago
8 0

To solve this problem, the first thing we should do is eliminate the parentheses in the expression.  To do this, we must understand that subtraction of a negative equals a positive, meaning that we can get rid of the second set of parentheses and change the minus a negative to a plus sign.  If we do this, we get:

(-13w² + 13) + 2w²

Next, we can get rid of the parentheses around the first two terms because there is addition inside and outside of the parentheses.  Since there ins no multiplication or negatives, we can simply rewrite the same expression with no parentheses.

-13w² + 13 + 2w²

Now, we must combine like terms.  This means adding terms that have the same variable to the same degree.  in this case, we must add -13w² and 2w².  To do this, we simply add their coefficients, giving us:

-11w² + 13

Therefore, the expression directly above is your answer.

Hope this helps!


Rus_ich [418]3 years ago
5 0

First, keep in mind that two negatives make a positive:

-13w^2 + 13 + 2w^2

-11w^2 + 13

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Here is a table showing all 52 cards in a standard deck.
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We want to find the probability of drawing 3 red cards from a deck of 52 cards.

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Let's see how to get that probability.

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And we assume that all the cards have the same probability of being drawn. Then the probability of drawing a red card in the first draw is just the quotient between the number of red cards and the total number of cards, we get:

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If you want to learn more, you can read:

brainly.com/question/10224828

8 0
3 years ago
Full Explanation<br> Will mark Brainlist
NeTakaya

Answer:

Hope the picture will help you....

Note: I am not sure about my answer....

4 0
2 years ago
Can someone please help mee (20 points and i will give brainliest!!!)
FromTheMoon [43]

Answer:

a. y-intercept:(0,  -6), x-intercepts: (3, 0) and (-2, 0). vertex: (0.5, -6.25)

b. y-intercept: (0, 6), x-intercepts(3, 0) and (-2, 0). vertex: (0.5, 6.25)

Step-by-step explanation:

a:

 So finding the y-intercept is really easy and is simply when x=0. If you plug in 0 as x it makes y=(0)^2-0-6 which simplifies to -6, which is the y-intercept. As for the x-intercepts you can calculate that by using the quadratic equation x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\. In this case a=1, b=-1, c=-6. So plugging those values in you get x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(-6)}}{2(1)}, which simplifies to x=\frac{1\pm5}{2}. This gives you the x-intercepts 6/2 and -4/2 which are 3 and -2. The vertex can be calculated by manipulating the equation so it's in the form of y=(x-h)^2+k where (h, k) is the vertex of the parabola. This is done by moving c to the other side and then completing the square and the isolating y. So the first step will be

Move c to the other side

y+6=x^2-x

Complete the square by adding (b/2)^2

y+6+0.25 = x^2-x+0.25

Rewrite as square binomial

y+6.25 = (x-0.5)^2

Isolate y

y=(x-0.50)^2-6.25

(h, k) = 0.50, -6.25 which is the vertex

b: To identify the y-intercept you plug in 0 as x which will only leave c which in this case is 6 which is the y-intercept. (0, 6). To identify the x-intercepts you can simplify plug in the values a, b, c into the quadratic equation which was stated in the previous answer. In this case a, b, c = -1, 1, 6. Plugging these values in gives the equation y=\frac{-(1)\pm\sqrt{1^2-4(-1)(6)}}{2(-1)}. which simplifies to x=\frac{-1\pm5}{-2} which gives the values -2 and 3. To find the vertex it's the same process as before

Factor out -1

y=-(x^2-x-6)

Add 6 to both sides (on the left side add -6 since -1 was factored out).

y-6=-(x^2-x)

Complete the square by adding (b/2)^2 to both sides (add -(b/2)^2 to left side since -1 was factored out)

y-6-0.25 = -(x^2-x+0.25)

Rewrite as square binomial

y-6.25=-(x-0.5)^2

Add 6.25 to both sides

y=(x-0.50)^2+6.25

(h, k) = (0.50, 6.25)

When you graph the parabolas you'll notice there just flipped relative to the x-axis. This can be deduced by simply looking at the two equations, since the two equations have the same absolute value coefficients, the signs are just different, and more specifically they're all opposite. If you took the first equation and multiplied the entire right side by -1 you would get the same equation. And since that equation really represents the value of y (since it's equal to y) you're reflecting it across the x-axis.

4 0
1 year ago
Read 2 more answers
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