<span>k = 1.7 x 10^5 kg/s^2
Player mass = 69 kg
Hooke's law states
F = kX
where
F = Force
k = spring constant
X = deflection
So let's solve for k, the substitute the known values and calculate. Don't forget the local gravitational acceleration.
F = kX
F/X = k
115 kg* 9.8 m/s^2 / 0.65 cm
= 115 kg* 9.8 m/s^2 / 0.0065 m
= 1127 kg*m/s^2 / 0.0065 m
= 173384.6154 kg/s^2
Rounding to 2 significant figures gives 1.7 x 10^5 kg/s^2
Since Hooke's law is a linear relationship, we could either use the calculated value of the spring constant along with the local gravitational acceleration, or we can simply take advantage of the ratio. The ratio will be both easier and more accurate. So
X/0.39 cm = 115 kg/0.65 cm
X = 44.85 kg/0.65
X = 69 kg
The player masses 69 kg.</span>
Given : A car starts from rest and retains the acceleration of 4m/s² in 20 second. Calculate its final velocity.
Solution : As we know that a car starts from rest so it's initial velocity should be 0 m/s. Acceleration is 4 m/s² and time taken is 20 sec. So, we need to calculate it's final velocity which we can get it usi g the first equation of motion.
First Equation of Motion : v = u + at
Putting all the required values in the formula we will get v
<u>Henceforth, final velocity is 80 m/sec.</u>
The first thing you should do in this case is to realize that you have two different materials.
First we make a free body diagram.
Then, we use the definitions of mechanics to find the forces.
Finally we substitute the values to find the normal stress due to the load.
Solution attached.
Answer:
Hi myself Shrushtee
Explanation:
Neutral carbon-12 (or any carbon atom) has 6 electrons with a total negative charge of 6e- orbiting a nucleus with a total positive charge of 6e+, so that the total net charge is zero. The nucleus is made up of 6 protons, each with a positive charge of e+, and 6 neutrons, each with zero charge.
please mark me as brainleist
Electric and magnetic field vectors are perpindicalar to each other in a electromagnetic wave. Passing stay current through a straight conductor shows some magnetic flux.