Answer : 
.
Explanation:
It is given that,
Electric field strength, 
We know that,
Charge of electron, 
Mass of electron, 
From the definition of electric field, 
...............(1)
According to Newton's second law, F = ma..........(2)
From equation (1) and (2)
or
So, the horizontal component of acceleration of an electron is .
Hence, it is the required solution.
Answer: 10.3m/s
Explanation:
In theory and for a constant velocity the physics expression states that:
Eq(1): distance = velocity times time <=> d = v*t for v=constant.
If we solve Eq (1) for the velocity (v) we obtain:
Eq(2): velocity = distance divided by time <=> v = d/t
Substituting the known values for t=15s and d=155m we get:
v = 155 / 15 <=> v = 10.3
The jetliner is traveling against the wind. The net speed of the jetliner is
590 mph - 36 mph = 554 mph
The time it takes for the jetliner to arrive at the destination is
1850 miles / 554 mph = 3.34 hours
Answer:
Explanation:
Angular speed of the motion ( SHM )
ω = √k/m
= √(580/.23 )
= 50.20 radian /s
a ) Rate of doing work
= power = force x velocity
At the equilibrium position force becomes zero so
rate of doing work is zero.
b )
If a be the amplitude
1/2 k a² = 170
a = .7655 m
kinetic energy at equilibrium = 1/ 2 m v₀²
1/ 2 m v₀² = 170
.5 x 23 v₀² = 170
v₀ = 3.84 m /s which is the maximum velocity.
Given x = .66 where rate of doing work is to be calculated.
Force at x = ω² x
= 50.20² x .66 =
= 1663.22 N
Velocity v = v₀ √( a² - x² )
= 3.84 √( .7655² - .66 )
= 3.84 x .387
= 1.486 m/s
power = force x velocity
= 1663.22 x 1.486
= 2471.55 W .
