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Alla [95]
4 years ago
14

Discuss the relationship between electric and magnetic fields

Physics
1 answer:
erik [133]4 years ago
5 0
Electric and magnetic field vectors are perpindicalar to each other in a electromagnetic wave. Passing stay current through a straight conductor shows some magnetic flux.
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What do you mean ny speed?​
Brut [27]

Answer:

I think they mean it is really fast or fast paced

Explanation:

3 0
3 years ago
Ill mark brainliest!!!
navik [9.2K]

Answer: A

si, di, are expressed as negative and f is expressed as positive values.

Explanation:

When the object is located at a location in front of the focal point of a convex len, the image will always be located somewhere on the same side of the lens as the object. The image is located behind the object. In this case, the image will be an upright image and the image is enlarged

In this question, the relationship between the focal length, image distance di and object distance is

I/f = 1/di + 1/do that is

I/f - 1/di - 1/do = 0

The image size si is also negative since the image is a virtual image.

Therefore, si, di, are expressed as negative, f is expressed as positive values.

6 0
3 years ago
Cliff divers at Acapulco jump into the sea macias (fjm793) – Homework 3, 2d motion 19-20 – dowd – (WoffordWPHY11920 2) 4 from a
Stells [14]

Answer:

v = 7.67 m/s

Explanation:

Given data:

horizontal distance 11.98 m

Acceleration due to gravity 9.8 m/s^2

Assuming initial velocity is zero

we know that

h = \frac{gt^2}{2}

solving for t

we have

t = \sqrt{\frac{2h}{g}}

substituing all value for time t

t = \sqrt{\frac{2\times 11.98}{9.8}}

t = 1.56 s

we know that speed is given as

v = \frac{d}{t}

v =\frac{11.98}{1.56}

v = 7.67 m/s

7 0
3 years ago
Calculate the speed of a 3.5cm sound wave of frequency 8000Hz
LuckyWell [14K]
The answer to this question is 2400Hz
8 0
3 years ago
Read 2 more answers
Four point charges, each having a magnitude of 2:00 C, are fixed at the corners of a square whose edges are 4:00m long. Find the
Vikki [24]

Answer:

Explanation:

Distance of each of the charges from the center are equal . If this distance be d

d = .5 x length of diagonal of square

length of diagonal = 4√2

d = .5 x 4√2

= 2√2

potential at a point

V = k Q / r where k is a constant , Q is charge and r is distance of the point from the charge .

k = 9 x 10⁹

Total potential = \frac{9\times10^9\times3 \times2}{2\sqrt{2} } -\frac{9\times10^9 \times2}{2\sqrt{2} }

= \frac{9\times10^9 \times2\times2}{2\sqrt{2} }

= 9 √2 x 10⁹ V .

5 0
4 years ago
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