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3 years ago

Discuss the relationship between electric and magnetic fields

1 answer:

5 0

Electric and magnetic field vectors are perpindicalar to each other in a electromagnetic wave. Passing stay current through a straight conductor shows some magnetic flux.

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1. Bone has a Young’s modulus of about

Blababa [14]

As we know that

$Y = \frac{stress}{strain}$

now plug in all data into this

$1.8\times 10^{10} = \frac{1.68 \times 10^8}{strain}$

$strain = 9.33 \times 10^{-3}$

now from the formula of strain

$strain = \frac{\Delta L}{L}$

$9.33 \times 10^{-3} = \frac{\Delta L}{0.54}$

$\Delta L = 5.04 \times 10^{-3} m$

$\Delta L = 5.04 mm$

As we know that

pressure * area = Force

here we know that

$Area = 3.53 \times 11.6 = 40.95 m^2$

$P = 0.2 atm = 0.2 \times 1.01 \times 10^5 = 2.02\times 10^4 Pa$

now force is given as

$F = 40.95 \times (2.02\times 10^4) = 8.27 \times 10^5 N$

As we know that density of water will vary with the height as given below

$\rho = \frac{\rho_0}{1 - \frac{\Delta P}{B}}$

here we know that

$\Delta P = 2600 atm = 2600 \times 1.01 \times 10^5 = 2.63\times 10^8 Pa$

$B = 2.3 \times 10^9 N/m^2$

now density is given as

$\rho = \frac{1050}{1 - \frac{2.63\times 10^8}{2.3 \times 10^9}}$

$\rho = 1185.3 kg/m^3$

as we know that pressure changes with depth as per following equation

$P = P_o + \rho g h$

here we know that

$P = 3 P_0$

now we will have

$3P_0 = P_0 + \rho g h$

$2P_0 = \rho g h$

$2(1.01 \times 10^5) = 1025 (9.81)(h)$

here we will have

$h = 20.1 m$

so it is 20.1 m below the surface

Here net buoyancy force due to water and oil will balance the weight of the block

so here we will have

$mg = \rho_1V_1g + \rho_2V_2g$

$A(0.0476)979 = 922(A)(0.0476 - x) + 1000(A)(x)$

$46.6 = 43.89 - 922x + 1000x$

$x = 3.48 cm$

so it is 3.48 cm below the interface

5 0

3 years ago

There is a 90 kg woman attached at the end of a bungee cord (k = 35 N/m) that is experiencing simple harmonic motion. How long d

Cloud [144]

Answer:

The value is $T =10.1 \ s$

Explanation:

From the question we are told that

The mass of the woman is $m = 90 \ kg$

The spring constant of the bungee cord is $k = 35 \ N/ m$

Generally the period of the oscillation (i,e time taken to complete on cycle ) is mathematically represented as

$T = 2 \pi * \sqrt{ \frac{m}{k} }$

=> $T = 2 * 3.142 * \sqrt{ \frac{90 }{ 35} }$

=> $T =10.1 \ s$

3 0

3 years ago

A light ray moving from oil (n=1.38) into an unknown material. If the light is incident at 35 and refracts at 23, what is the in

Nastasia [14]

The index of refraction of the unknown material in which a ray of light is incident at 35° and refracted at 23° is 2.03

<h3>Snell's law</h3>

index of refraction (n) = Sine i / Sine r

n = Sine i / Sine r

Where

i is the angle of incidence
r is the angle of refraction

<h3>How to determine the refractive index </h3>

From the question given above, the following data were obtained:

Index of refraction of oil (nₒ) = 1.38
Angle of incidence (i) = 35°
Angle of refraction (r) = 23°
Index of refraction of unknown material (nᵣ) =?

nₒSine i = nᵣSine r

1.38 × Sine 35 = nᵣ × Sine 23

Divide both side by Sine 23

nᵣ = (1.38 × Sine 35) / Sine 23

nᵣ = 2.03

Thus, the index of refraction of the unknown material is 2.03

Learn more about Snell's law:

brainly.com/question/25758484

7 0

2 years ago

Science Will give brainless and 22 points

fenix001 [56]

Answer:

Mercury 0.39 AU, 36 million miles

57.9 million km

Venus 0.723 AU

67.2 million miles

108.2 million km

Earth 1 AU

93 million miles

149.6 million km

Mars 1.524 AU

141.6 million miles

227.9 million km

Jupiter 5.203 AU

483.6 million miles

778.3 million km

Saturn 9.539 AU

886.7 million miles

1,427.0 million km

Uranus 19.18 AU

1,784.0 million miles

2,871.0 million km

Neptune 30.06 AU

2,794.4 million miles

4,497.1 million km

Pluto (a dwarf planet) 39.53 AU

3,674.5 million miles

5,913 million km

4 0

3 years ago

Read 2 more answers

Would this officer calculate a higher value of Edef, a lower value of Edef, or the same value of Edef if he used the velocities

NISA [10]

Answer:

<em>The officer would calculate the similar value of Edef.</em>

Explanation:

As Edef is the energy required to deform the body therefore the reference frame does not affect the calculation of energy. In this context the value of Edef will remain same irrespective of fact, whichever frame of reference is used.

4 0

3 years ago