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Burka [1]
4 years ago
5

The sound level produced by one singer is 76.7 dB. What would be the sound level produced by a chorus of 41 such singers (all si

nging at the same intensity at approximately the same distance as the original singer)? Answer in units of dB.
Physics
1 answer:
MatroZZZ [7]4 years ago
6 0

Answer:

In dB intensity will be equal to 159.74 dB

Explanation:

We have given intensity of sound produced by one singer is 76.7 dB

Sound intensity is calculated as I(dB)=10log\frac{I}{10^{-12}}

76.7=10log\frac{I}{10^{-12}}

10^{7.67}=\frac{I}{10^{-12}}

I=4.677\times 10^{-5} W/m^2

Now it is given that 41 singers are singing in chorus

So total intensity = I=41\times 4.677\times 10^{-5}=191.757\times 10^{-5}W/m^2

Now in dB intensity will be

I(dB)=10log\frac{191.757\times 10^{-5}}{10^{-12}}=159.74dB

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A process generates 250 watts of useful energy and 600 watts of waste energy. WhT is the efficiency of the process?
Cloud [144]

The efficiency of the process is 42%

From the question given above, the following data were obtained:

Useful energy = 250 watt

Wasteful energy = 600 watt

<h3>Efficiency =? </h3>

The efficiency of the process can be obtained as illustrated below:

efficiency \:  =  \frac{useful \: energy}{wasteful \: energy}  \times 100 \\  \\ efficiency \:  =  \frac{250}{600}  \times 100 \\

<h3>Efficiency = 42%</h3>

Therefore, the efficiency of the process is 42%

Learn more: brainly.com/question/2300041

3 0
3 years ago
Please need help on this I know it’s not D an atom.
Alchen [17]
A reactant since it is on the left of the arrow
8 0
3 years ago
In a physics lab, light with a wavelength of 570 travels in air from a laser to a photocell in a time of 16.5 . When a slab of g
aliina [53]

Answer:

Wavelength is calculated as 213.9 nm

Solution:

As per the question:

Wavelength of light = 570 nm

Time, t = 16.5 ns

Thickness of glass slab, d = 0.865 ns

Time taken to travel from laser to the photocell, t' = 21.3

Speed of light in vacuum, c = 3\times 10^{8}\ m/s

Now,

To calculate the wavelength of light inside the glass:

After the insertion of the glass slab into the beam, the extra time taken by light to cover a thickness t = 0.865 m is:

t' - t = 21.3 - 16.5 = 4.8 ns

Thus

\frac{d}{\frac{c}{n}} - \frac{d}{v} = 4.8\times 10^{- 9}

\frac{0.8656}{\frac{c}{n}} - \frac{0.865}{v} = 4.8\times 10^{- 9}

where

n = refractive index of the medium

v = speed of light in medium

\frac{0.8656}{\frac{c}{n}} - \frac{0.865}{v} = 4.8\times 10^{- 9}

n = \frac{4.8\times 10^{- 9}\times 3.00\times 10^{8}}{0.865} + 1

n = 2.66

Now,

The wavelength in the glass:

\lambda' = \frac{\lambda }{n}

\lambda' = \frac{570}{2.66} = 213.9\ nm

5 0
4 years ago
In the diagram, each charge is
Jlenok [28]

Answer:

Quick maths

First you find the fafarick and the lalickc and the caprisum and the joinnt

3 0
3 years ago
A 5.00-g bullet is fired into a 900-g block of wood suspended as a ballistic pendulum. The combined mass swings up to a height o
Thepotemich [5.8K]

Answer:

The value is  KE_b =0.710 \ J

Explanation:

From the question we are told that

   The mass  of the bullet is m_b  = 5.00 \ g  = 0.005 \  kg

  The mass  of the wood is  m_w =  900 \  g  =  0.90\  kg

   The height attained by the combined mass is  h =  8.0 \ cm  =  0.08 \ m

Generally according to the law of energy conservation    

    KE _b  =  PE_c

Here KE_b is the kinetic energy of the bullet before collision.

and PE_c is the  potential  energy of the combined mass of bullet and wood at the height h which is mathematically represented as

      PE_m  =  [m_b  + m_w] *  g *  h

So

   KE_b =PE_c   = [0.005  + 0.90] * 9.8 *0.08

=> KE_b =0.710 \ J

3 0
3 years ago
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