Question

The sound level produced by one singer is 76.7 dB. What would be the sound level produced by a chorus of 41 such singers (all singing at the same intensity at approximately the same distance as the original singer)? Answer in units of dB.

Answer 1

Answer:

In dB intensity will be equal to 159.74 dB

Explanation:

We have given intensity of sound produced by one singer is 76.7 dB

Sound intensity is calculated as $I(dB)=10log\frac{I}{10^{-12}}$

$76.7=10log\frac{I}{10^{-12}}$

$10^{7.67}=\frac{I}{10^{-12}}$

$I=4.677\times 10^{-5}$ $W/m^2$

Now it is given that 41 singers are singing in chorus

So total intensity = $I=41\times 4.677\times 10^{-5}=191.757\times 10^{-5}W/m^2$

Now in dB intensity will be

$I(dB)=10log\frac{191.757\times 10^{-5}}{10^{-12}}=159.74dB$