12a+6b equivalent expression

Mathematics

1 answer:

patriot [66]3 years ago

5 0

Answer:

$6(2a+b)$

Step-by-step explanation:

The given expression is

$12a+6b$

To find the equivalent expression of the given one, we just have to factor.

In this case, the only thing we can do to rewrite is to extract the common greatest factor, which is 6

$12a+6b\\6(2a+b)$

Therefore, the equivalent expression is

$6(2a+b)$

You might be interested in

Ashley has a box of donuts to distribute among her colleagues. There are eight chocolate donuts, twelve glazed donuts, ten jelly

Serjik [45]

According to one source, the answer is "C. Randomly select and replace a donut 72 times. Then, observe how close to 18 times a glazed donut is drawn. "

Thank you for your question. Please don't hesitate to ask in Brainly your queries.

8 0

3 years ago

Read 2 more answers

John is playing a game with a standard deck of playing cards. He wants to draw a jack on the first try. Which of the following s

Tatiana [17]

Answer:

Step-by-step explanation:

It is a 1/13 chance but even if you shuffle and replace it, its still a 1/13 chance.

4 0

3 years ago

Read 2 more answers

It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi

Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that $\mu = 35000, \sigma = 7000$

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

$Z = \frac{X - \mu}{\sigma}$

$-1.88 = \frac{X - 35000}{7000}$