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Degger [83]
4 years ago
11

Please help! Same answer choices for both of the drop down menus...

Mathematics
1 answer:
Artyom0805 [142]4 years ago
5 0

the first one is left and the second one is up

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Write the next three terms of the arithmetic sequence 60,30,0,-30
Gekata [30.6K]
-60 -90 -120 it’s going by -30 and that should figure out the next three te rms
4 0
3 years ago
Marta is making two different charms for necklace one charm has a 1 cm diameter and a 3.14 cm circumference of a similar charm h
EastWind [94]
From what I can pick up from your problem statement, you want to know "<span>a similar charm has a diameter of 4 cm what is the circumference."  Please, would you use proper punctuation in your writing, for greater clarity:

"A</span><span> similar charm has a diameter of 4 cm.  What is the circumference?"

The formula for the circumference of a circle, when the diameter is known, is 

C=</span>\pid               or  C=pi*d

In this case, with diamter 4 cm, the circumference, C, is 4pi cm.
3 0
3 years ago
Identify the domain and range of the relation:<br> (-5,-3), (-2,1), (1,4), (2,5)
jonny [76]

Domain is the x-coordinate and range is the y - coordinate

\therefore \: domain =  \{ - 5, \:  - 2, \: 1, \: 2 \} \\  \\ \&\: range =  \{  - 3, \: 1, \: 4, \: 5\}

3 0
3 years ago
A sum of money is invested at 12% compounded quarterly. About how long will it take for the amount of money to double?
Fofino [41]
Follow the given formula.  The initial amount of money invested, P, becomes 2P (same thing as "doubles) after t years.  Since compounding is quarterly, n=4.  The annual interest rate is 12%.  That is, r=0.12.

Then we have 2P = P (1 + 0.12/4)^(4t) and need only solve for time, t.

Simplifying the above equation:  2 = (1.03)^(4t)

We must isolate 4t, and then isolate t.  To do this, take the common log of both sides of the above equation.  We get:

log 2 = (4t) log 1.03.  This gives us 4t = [log 2] / [log 1.03], or

4t =  23.4498

Dividing both sides by 4, we get     t = 5.86 (years).
7 0
4 years ago
If the diagonals of a quadrilateral do not bisect each other then the quadrilateral could be a
Svet_ta [14]
Trapezoid. The diagonals of all parallelograms bisect each other. Trapezoid are not parallelograms.
8 0
3 years ago
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