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Korolek [52]
3 years ago
6

In solving \\(x^{2}=3\\) we obtain _______

Mathematics
1 answer:
Xelga [282]3 years ago
3 0

For this case we must solve the following equation:

x ^ 2 = 3

So we have to:

Applying square root to both sides of the equation:

x = \pm \sqrt {3}

Thus, we have two roots:

x_ {1} = \sqrt {3} = 1.7321\\x_ {2} = - \sqrt {3} -1.7321

Answer:

x_ {1} = 1.7321\\x_ {2} = - 1.7321

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2/3 of the sum of three times a number and six is 10. what is the number?
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Answer:

  3

Step-by-step explanation:

Let x represent the number. The problem statement tells you ...

2/3(3x +6) = 10

  2x +4 = 10 . . . . . . use the distributive property

  x +2 = 5 . . . . . . . . divide by 2

  x = 3 . . . . . . . . . . .subtract 3

The number is 3.

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<em>Comment on the solution</em>

The above shows an "alternative" solution method. The more usual way this might be done is ...

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  6x +12 = 30 . . . . . . . eliminate parentheses

  6x = 18 . . . . . . . . . . . subtract 12

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3 years ago
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6 0
3 years ago
Which of the following is the interest on $6000 at 6% compounded semiannually for eight years?
ryzh [129]

Answer:

$3628.24

Step-by-step explanation:

we use the formula for accrued value (A) with compounded interest:

A=P(1+\frac{r}{n})^{n*t}

where A= accrued value (principal plus the accumulated  interest)

P = principal -> in our case $6000

r = annual interest rate (in decimal form) -> in our case 0.06

n = number of compoundings per year. In our case 2 (semiannually)

t = time in years -> in our case 8

A=P(1+\frac{r}{n})^{n*t}\\A = 6000(1+\frac{0.06}{2})^{16}\\ A= 6000(1+0.03)^{16}\\A = $9628.24

Since this is the value of principal plus accumulated interest, we subtract from it the principal ($6000) to get the value of just the interest:

$9628.24 - $6000 = $3628.24

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3 years ago
How do you find the radius of a cylinder when you only know the surface area?
Paha777 [63]

The surface area of a cylinder with circular bases of radius <em>r</em> and height <em>h</em> is equal to the sum of the areas of the two circular faces and the area of the rectangular lateral surface:

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