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Flauer [41]
3 years ago
14

Use the rules of significant figures to find the answer to the addition problem S= 25.4+14+16.67+3.903

Mathematics
1 answer:
xenn [34]3 years ago
6 0
S=59.973 all you have to do now is round it. So the real answer is S=60. All i did was add up all the numbers.
25.4 + 16.67 = 42.07 + 3.903 = 45.973 + 14 = 59.973
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Find the simple interest for a $8,000 loan for 2 years at a rate of 4% (formula: l=prt)​
Natali [406]

Answer:

S.I= 640

Step-by-step explanation:

I=prt

where p= $8,000

and r= 4%

and t= 2 years

$8,000×4%×2

8,000×4/100×2

80×4×2

=640

Therefore The S.I = 640.

6 0
3 years ago
PLEASE HELP!! NO LINKS!!
dlinn [17]

Answer:

42.1 cm

Step-by-step explanation:

θ = 265°

Radius (r) = 9.1 cm

Arc length of major arc GH = θ/360 × 2πr

Plug in the values into the equation

Length of arc GH = 265/360 × 2 × π × 9.1

= 42.0886149

= 42.1 cm (nearest tenth)

6 0
3 years ago
Solve the inequality.<br><br> 5/6t - 3≥3t + 6
Papessa [141]

Answer:

t ≤ -\frac{54}{13}

Step-by-step explanation:

\frac{5}{6}t−3−3t≥3t+6−3t

-\frac{13}{6}t−3≥6

-\frac{13}{6}t−3+3≥6+3

\frac{13}{6}t≥9

-\frac{6}{13}(-\frac{13}{6}t) ≥ -\frac{6}{13}(9)

t ≤ -\frac{54}{13}

6 0
2 years ago
A certificate of deposit earns 1% interest every three months. The interest is compounded.
dsp73
A certificate of deposit earns 1% interest every three months. The interest is compounded.


What is the value of a $35,000 investment after 6 years?


$37,153.21

$39,438.88

$44,440.71

$56,295.30

A. 37,153.21
5 0
3 years ago
Read 2 more answers
Find the midpoint of the line segment whose endpoints are (2.6,5.1) and (3,4.7).
svp [43]

Answer:

Mid point is: (2.8;4.9)

Step-by-step explanation:

To find midpoint of a line segment we can use the general equation:

Mid=\frac{x_1+x_2}{2} ;\frac{y_1+y_2}{2}

Where the point of the line are: (x₁;y₁) and (x₂;y₂).

In the problem, x₁ = 2.6, y₁ = 5.1 and x₂ = 3 and y₂ = 4.7. Replacing in the equation:

Mid=\frac{2.6+3}{2} ;\frac{5.1+4.7}{2}

<h3>Mid point is: (2.8;4.9)</h3>

7 0
3 years ago
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