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ankoles [38]
3 years ago
15

What is the value of x in the right triangle below? Show your work and round your answer to the nearest hundredth. ​

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0

The length of the hypothenuse or the value of x is equal to 19.53

Data;

  • hypothenuse = x
  • adjacent = 11.2
  • opposite = 16
<h3>Pythagoras's Theorem</h3>

To solve this problem, we have to use Pythagoras's theorem which is used to find the missing side in a right angle triangle if we have at least two sides.

The formula for this is

x^2 = y^2 + z^2\\

Let's substitute the values and solve for the missing side

x^2 = 16^2 + 11.2^2 \\x^2 = 256 + 125.44\\x^2 = 381.44\\x = \sqrt{381.44} \\x = 19.53

The length of the hypothenuse or the value of x is equal to 19.53

Learn more Pythagoras theorem here;

brainly.com/question/3317136

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because the parabola opens downwards, "p" is negative, and thus, -2

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\bf \begin{array}{llll}&#10;(x-{{ h}})^2=4{{ p}}(y-{{ k}})\\&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ({{ h}},{{ k}})\\&#10;{{ p}}=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;&#10;\begin{cases}&#10;h=3\\&#10;k=3\\&#10;p=-2&#10;\end{cases}\implies (x-3)^2=4(-2)(y-3)\implies (x-3)^2=-8(y-3)&#10;\\\\\\&#10;-\cfrac{(x-3)^2}{8}=y-3\implies \boxed{-\cfrac{1}{8}(x-3)^2+3=y}

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3 years ago
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