All categories

2 years ago

How to do the substitution in math?

Mathematics

1 answer:

seraphim [82]2 years ago

4 0

Substitution method can be applied in four steps

Step 1:

Solve one of the equations for either <span>x = </span>or y = .

Step 2:

Substitute the solution from step 1 into the other equation.

Step 3:

Solve this new equation.

Step 4:

Solve for the second variable.

hope this helps you!

You might be interested in

Solve the math problem please

koban [17]

Answer:

Option D

Step-by-step explanation:

Collect all like terms and Calculate

-10x-7x= -17x

20-54= -34

Divide

-17x < -34

x>2

6 0

3 years ago

Read 2 more answers

25 POINTS!! PRE-ALGEBRA MATH! PLEASE HURRY! I WILL GIVE BRAINLIEST!

yan [13]

Answer: We are using a line regression tool to solve the parameters asked in the problem. We can use online tools or that of Excel. According to the tool, the best fit values are

Slope0.3848 ± 0.03956

Y-intercept0.6053 ± 0.6370

X-intercept-1.573

1/Slope2.598

Step-by-step explanation: Best fit lines make sure that the standard deviation at each point is minimum from the best fit line.

3 0

2 years ago

Read 2 more answers

For the month of March in a certain city, 57% of the days are cloudy. Also in the month of March in the same city, 55% of the da

oksian1 [2.3K]

Answer: 0.9649

Step-by-step explanation:

Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.

Given : For the month of March in a certain city, the probability that days are cloudy : $P(A)=0.57$

Also in the month of March in the same city,, the probability that the days are cloudy and rainy : $P(A\cap B)=0.55$

Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}$

$\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}$

Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649

4 0

3 years ago

If there are five different breads, eight meats, five cheeses, and five special sauces, how many different sandwiches are possib

Papessa [141]

Answer:

There are 1000 different sandwiches possible.

Step-by-step explanation:

The number of breads available is, 5.

The number of meats available is, 8.

The number of cheese available is, 5.

The number of special sauces available is, 5.

Assuming that a person is allowed 1 selection of each category.

The possible number of sandwiches that can be made is:

$=5\times8\times5\times5\\=1000$

Thus, there are 1000 different sandwiches possible.

6 0

3 years ago

Write an equation of the line that passes through (5, −1) and is perpendicular to the line y=12x−1.

Lisa [10]

Step-by-step explanation:

solution

let,A(5,-1)

given

y=12x-1

or, y = 12 × x + (-1)

comparing it with y=mx+c

we get

x=1

y = c = -1

now

A(5,-1) and B(1,-1)

equation of line is,

(y-y1)/(x-x1) = (y2-y1)/(x2-x1)

or, (y+1)/(x-5) = (-1+1)/(1-5)

or, (y+1)/(x-5) = 0/-4

cross multiply

-4y-4 = 0

or, 0=4y+4

or, 4y+4=0 is the required eqn

I think this is the process and answer too.

I hope this helps you

4 0

3 years ago