ANSWER
The length of the conjugate axis is 6 units.
EXPLANATION
The given hyperbola has equation:

We can rewrite this equation in the form:

We compare this equation to:

This implies that;

and

The length of the conjugate axis of a hyperbola is

Substitute b=3 to obtain;

Hope this is the right one.
Problem 8p^2 - 30p + c
<em>Step One</em>
Take 1/2 of - 30
1/2 * -30 = - 15
<em>Step 2
</em>Square -15
(-15)^2 = 225
c = 225
Problem Nine
a = 1
b = 4
c = -15


x = [-4 +/- sqrt(76)] / 2
x = [-4 +/- 2*sqrt19]/2
x = [-4/2 +/- 2/2 sqrt[19]
x = - 2 +/- sqrt(19)
x1 = - 2 + sqrt(19)
x2 = -2 - sqrt(19)
These two can be broken down more by finding the square root. I will leave them the way they are. It's just a calculator question if you want it to go into decimal form.
Problem Tena = 1
b = 4
c = -32
The discriminate is sqrt(b^2 - 4ac)
D = sqrt(b^2 - 4ac)
D = sqrt(4^2 - 4(1)(-32)
D = sqrt(16 - - 128)
D = sqrt(16 + 128)
D = sqrt(144)
D = +/- 12
Since D can equal + or minus 12 there must be 2 possible (and different) roots. As a matter of fact, this quadratic can be factored.
(x + 8)(x - 4) = y
But that' s not what you were asked for.
The discriminate is > 0 so the roots are going to be real.
<em>
Answer; The discriminate is > 0 so there will be 2 real different roots.</em>
Using the law of sins:
side a / sin (angle A) = side b / sin(Angle B)
Side a is opposite angle A, so from the picture we know side a = 50, angle A is 58 degrees and angle B is 48 degrees.
replace those values in the formula we get:
50 / sin(58) = b/ sin(48)
so now we can cross multiply the 2 fractions to get:
50 * sin(48) = b*sin(58)
to get b by itself, divide both sides by sin(58) to get:
b = (50*sin(48)) / sin(58)
b = 43.82
You may need to round the answer as needed.
Answer:
20 mg/ml.
Step-by-step explanation:
We have been given that a liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle.

To convert the concentration of morphine sulfate on a mg/mL basis, we need to convert 2.4 grams to milligrams.
1 gram equals 1000 milligrams.




Therefore, the concentration of morphine sulfate would be 20 mg per ml.
It is the transformation shown in (B)
(look at one point of the letter P and how it moves precisely 3 units. Also there is only the move, no flipping of the figure)