The angle of the plane when it rose from the ground is 64.8 degrees
<h3>Application of trigonometry identity</h3>
Given the following parameters from the question
Altitude of the airplane H = 500m
Horizontal distance from airport "d" = 235
Required
angle of elevation
According to the trigonometry identity
tan x = opposite/adjacent
tan x = H/d
tan x = 500/235
tan x = 2.1277
x = arctan(2.1277)
x = 64.8 degrees
The angle of the plane when it rose from the ground is 64.8 degrees
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The angle that is next to 9x should be 180 - 9x because it is a straight angle.
Since there are 180 degrees in an angle we can add up the values to 180 and solve for x.
180- 9x + 5x + 9 + x = 180
-3x = -9
x = 3
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