Answer:
It will take 50 years to decay from 512 grams to 121.5 grams.
Step-by-step explanation:
The decay formula :
![N=N_0e^{-\lambda t}](https://tex.z-dn.net/?f=N%3DN_0e%5E%7B-%5Clambda%20t%7D)
where
N= amount of substance after t time
N₀= initial of substance
t= time.
A substance decays at a rate 25% every 10 years.
So, remaining amount of the substance is = (100%-25%)= 75%
, t= 10
![N=N_0e^{-\lambda t}](https://tex.z-dn.net/?f=N%3DN_0e%5E%7B-%5Clambda%20t%7D)
![\Rightarrow \frac {N}{N_0}=e^{-\lambda t}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cfrac%20%7BN%7D%7BN_0%7D%3De%5E%7B-%5Clambda%20t%7D)
![\Rightarrow \frac34 =e^{-\lambda .10}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cfrac34%20%3De%5E%7B-%5Clambda%20.10%7D)
Taking ln both sides
![\Rightarrow ln|\frac34| =ln|e^{-\lambda .10}|](https://tex.z-dn.net/?f=%5CRightarrow%20ln%7C%5Cfrac34%7C%20%3Dln%7Ce%5E%7B-%5Clambda%20.10%7D%7C)
![\Rightarrow ln|\frac34|=-10\lambda](https://tex.z-dn.net/?f=%5CRightarrow%20ln%7C%5Cfrac34%7C%3D-10%5Clambda)
![\Rightarrow \lambda=\frac{ ln|\frac34|}{-10}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Clambda%3D%5Cfrac%7B%20ln%7C%5Cfrac34%7C%7D%7B-10%7D)
Now , N₀= 512 grams, N= 121.5 grams, t=?
![N=N_0e^{-\lambda t}](https://tex.z-dn.net/?f=N%3DN_0e%5E%7B-%5Clambda%20t%7D)
![\therefore 121.5=512e^{-\frac{ln|\frac34|}{-10}.t}](https://tex.z-dn.net/?f=%5Ctherefore%20121.5%3D512e%5E%7B-%5Cfrac%7Bln%7C%5Cfrac34%7C%7D%7B-10%7D.t%7D)
![\Rightarrow 121.5=512e^{\frac{ln|\frac34|}{10}.t}](https://tex.z-dn.net/?f=%5CRightarrow%20121.5%3D512e%5E%7B%5Cfrac%7Bln%7C%5Cfrac34%7C%7D%7B10%7D.t%7D)
![\Rightarrow \frac{121.5}{512}=e^{\frac{ln|\frac34|}{10}.t}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cfrac%7B121.5%7D%7B512%7D%3De%5E%7B%5Cfrac%7Bln%7C%5Cfrac34%7C%7D%7B10%7D.t%7D)
Taking ln both sides
![\Rightarrow ln|\frac{121.5}{512}|=ln|e^{\frac{ln|\frac34|}{10}.t}|](https://tex.z-dn.net/?f=%5CRightarrow%20ln%7C%5Cfrac%7B121.5%7D%7B512%7D%7C%3Dln%7Ce%5E%7B%5Cfrac%7Bln%7C%5Cfrac34%7C%7D%7B10%7D.t%7D%7C)
![\Rightarrow ln|\frac{121.5}{512}|={\frac{ln|\frac34|}{10}.t}](https://tex.z-dn.net/?f=%5CRightarrow%20ln%7C%5Cfrac%7B121.5%7D%7B512%7D%7C%3D%7B%5Cfrac%7Bln%7C%5Cfrac34%7C%7D%7B10%7D.t%7D)
![\Rightarrow t=\frac{ln|\frac{121.5}{512}|}{\frac{ln|\frac34|}{10}}](https://tex.z-dn.net/?f=%5CRightarrow%20t%3D%5Cfrac%7Bln%7C%5Cfrac%7B121.5%7D%7B512%7D%7C%7D%7B%5Cfrac%7Bln%7C%5Cfrac34%7C%7D%7B10%7D%7D)
![\Rightarrow t=\frac{10.ln|\frac{121.5}{512}|}{{ln|\frac34|}}](https://tex.z-dn.net/?f=%5CRightarrow%20t%3D%5Cfrac%7B10.ln%7C%5Cfrac%7B121.5%7D%7B512%7D%7C%7D%7B%7Bln%7C%5Cfrac34%7C%7D%7D)
⇒t=50 years
It will take 50 years to decay from 512 grams to 121.5 grams.
4x+4y+4z. I was taught to take out what was in each term, in this problem that would be 4: 4(X+y+z). Meaning A) Annie did the problem right :) I hope this helps!
Answer:
2020
Step-by-step explanation:
2020
Answer:
25
Step-by-step explanation:
Each of the 16 "ratio units" representing all 80 dancers must stand for ...
(80 dancers)/(16) = 5 dancers
Then 5 "ratio units" representing seventh-grade dancers will stand for ...
5 × 5 dancers = 25 dancers
___
Another way to figure this is to write the proportion ...
(seventh-grade dancers)/(all dancers) = 5/16
seventh-grade dancers = (all dancers)×(5/16) = 80×5/16
seventh-grade dancers = 25
Answer:
The answer is D!!!
Step-by-step explanation:
In the attachment!
I plugged in that equation into a graphing calculator and got this....
since it's also a (<, >) sin, we know that it's dotted.....
Hope this helps!