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3 years ago

Given g(x)= -2x+2 and f(x)= 3x^2+4, find (g+f)(-3)

Mathematics

1 answer:

aliina [53]3 years ago

3 0

Answer:

Step-by-step explanation:

g(x)= -2x+2 and f(x)= 3x^2+4

(g+f)(-3)

g(-3) = -2(-3) +2 = 6+2 =8

f(-3) = 3 (-3)^2 +4 = 3(9)+4 = 27+4 = 31

(g+f)(-3) = g(-3) + f(-3) = 8+31 = 39

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Which features describe the graph of

Arisa [49]

Answer:

4. a vertex at (0, 96) is CORRECT

5. the center at (0, 0) is CORRECT

From the given equation,

a = 40

b = 96

(h,k) = (0,0), the center

The vertices are at (0,96) and at (0, -96).

The curves open upward and downward.

c² = a² + b² = 40² + 96² = 10816

c = 104

Therefore the foci are at (0, -104) and (0, 104).

Check the given answers:

1. a focus at (104, 0) is INCORRECT

2. a focus at (0, -96) is INCORRECT

3. a vertex at (-40, 0) is INCORRECT

4. a vertex at (0, 96) is CORRECT

5. the center at (0, 0) is CORRECT

Read more on Brainly.com - brainly.com/question/4411338#readmore

4 0

3 years ago

Read 2 more answers

Last years freshman class at big state university totaled 5,305 students of those 1258 received a merit scholarship to help offs

Leokris [45]

Using the normal distribution, it is found that 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation for the amounts are given as follows:

$\mu = 3456, \sigma = 478$

The proportion is the p-value of Z when X = 4250, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4250 - 3456}{478}$

Z = 1.66

Z = 1.66 has a p-value of 0.9515.

Hence 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.

More can be learned about the normal distribution at brainly.com/question/15181104

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4 0

2 years ago

A plant that is 6 inches tall grows 1 inch each week. Another plant is 4 inches tall and grows 2 inches each week

Darya [45]

2 weeks, because the first week the second plant will grow to 6 inches and the first plant will grow to 7, the next week the first plant will be 8 inches and so will the second plant.

4 0

2 years ago

(Based on Q1 ~ Q3) According to the Bureau of the Census, 18.1% of the U.S. population lives in the Northeast, 21.9% inn the Mid

vekshin1

Answer:

We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

The populations considered are the Midwest, South, Northeast, and west.

The number of categories, k = 4

Number of recent calls = 200

Let the number of estimated parameters that must be estimated, m = 0

The degree of freedom is given by the formula:

df = k - 1-m

df = 4 -1 - 0 = 3

Let the significance level be, α = 5% = 0.05

For α = 0.05, and df = 3,

from the chi square distribution table, the critical value = 7.815

Observed and expected frequencies of calls for each of the region:

Northeast

Observed frequency = 39

It contains 18.1% of the US Population

The probability = 0.181

Expected frequency of call = 0.181 * 200 = 36.2

Midwest

Observed frequency = 55

It contains 21.9% of the US Population

The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

South

Observed frequency = 60

It contains 36.7% of the US Population

The probability = 0.367

Expected frequency of call = 0.367 * 200 = 73.4

West

Observed frequency = 46

It contains 23.3% of the US Population

The probability = 0.233

Expected frequency of call = 0.233 * 200 = 46

$x^{2} = \sum \frac{(O_{i} - E_{i}) ^{2} }{E_{i} } , i = 1, 2,.........k$

Where $O_{i} =$ observed frequency

$E_{i} =$ Expected frequency

Calculate the test statistic value, x²

$x^{2} = \frac{(39 - 36.2)^{2} }{36.2} + \frac{(55 - 43.8)^{2} }{43.8} + \frac{(60 - 73.4)^{2} }{73.4} + \frac{(46 - 46.6)^{2} }{46.6}$

$x^{2} = 5.535$

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

7 0

3 years ago

Explanation please will give brainliest.

Sonja [21]

Answer:

$AC = 28$