The number of seconds in a year are 31,557,600 seconds, which gives;
There are approximately Pi times 10,000,000 seconds in one <u>year</u>.
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<h3>How can the given statement be completed?</h3>
The number of seconds in one day = 86,400
The number of seconds in one week = 604,800
The number of seconds in a year = 31,557,600
Therefore;
Which gives;
The number of seconds in a year ≈ π × 10,000,000
The completed statement is therefore;
- There are approximately Pi times 10,000,000 seconds in one <u>year</u>
Learn more about conversion of units here:
brainly.com/question/599249
Answer:
Step-by-step explanation:
Give the DE
dy/dx = 1-y
Using variable separable method
dy = (1-y)dx
dx = dy/(1-y)
Integrate both sides
∫dx = ∫dy/(1-y)
∫dy/(1-y)= ∫dx
-ln(1-y) = x+C
ln(1-y)^-1 = x+C
Apply e to both sides
e^ln(1-y)^-1 = e^,(x+C)
(1-y)^-1 = Ce^x
1/(1-y) = Ce^x
Answer:
Step-by-step explanation:
1). m∠AEC = m∠AEB + m∠BEC
= 21° + 37°
= 58°
2). m∠BED = m∠BEC + m∠CED
= 37° + 44°
= 81°
3). m∠IKF = m∠IKH + m∠HKG + m∠GKF
= m∠IKH + m∠HKG + m∠IKH [Since, ∠IKH ≅ ∠GKF]
= 2∠IKH + m∠HKG
103° = 2∠IKH + 41°
2(∠IKH) = 103 - 41
m(∠IKH) = 31°
4). m∠AED = m∠AEB + m∠BEC + m∠CED
= 21° + 37° + 44°
= 102°
5). m∠JKG = 108°
m∠JKG = m∠JKI + m∠IKH + m∠HKG
108° = m∠JKI + 31° + 41°
m∠JKI = 108° - 72°
m∠JKI = 36°
6). m∠HKF = m∠GKF + m∠HKG
= m∠IKH + m∠HKG [Since, m∠GKF = m∠IKH]
= 31° + 41°
= 72°
7). m∠NQO = m∠MQN = 64°
8). m∠JKF = m∠JKI + m∠IKF
= 36° + 103°
= 139°
8). m∠MQO = 2(m∠NQO)
= 2(64)°
= 128°
9). m∠LQO = 156°
m∠LQM = m∠LQO - m∠MQO
= 156° - 128°
= 28°
10. m∠NQP = m∠NQO + m∠OQP
= 64° + m∠LQM [Since ∠OQP ≅ ∠LQM]
= 64° + 28°
= 92°
Answer:
Step-by-step explanation:
The sum is the result obtained from adding two or more values together.
The sum of <em>s</em> and <em>t</em> is the result obtained from adding <em>s</em> and <em>t</em> together.
<em>s </em>+<em> t</em>
