Answer:
The answer would be c
Step-by-step explanation:
I did it edge yesterday
Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
Step-by-step explanation:
No but it is close. (4x +13x +10) factors into
(4x + 5)(x + 2)
So (x + 2) is a factor along with (4x + 5)
8pi ft
Just divide 16 by 2 because it’s half of the diameter
Answer:
$2542.72 for everything
Step-by-step explanation:
$365.68*4=$1462.72 for the nikes
120*9.00=1080 for the peaches SO YOU ADD the $1462.72 and the *1080 which is $2542.72 for everything