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Alexxx [7]
3 years ago
10

I’m just wanting to know because this is really bugging me and I am having a brain fart. But if you have 10 assignments left and

still 68 days left in school. How many assignments per day would you need to complete in order to be done on time/early?
Mathematics
2 answers:
xz_007 [3.2K]3 years ago
6 0

Answer:

1 a day

Step-by-step explanation:

If you don't have a problem getting done early, then you should be able to do 1 a day, and get done in 10 days.

Butoxors [25]3 years ago
5 0

You would need to complete 10/68 of an assignment per day if I'm reading you right to finish on time

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\implies {\pink {\boxed {\boxed {\purple {\sf { \: x =  \frac{2}{7}}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

Let x be the unknown number.

As per the question, we have

\: ( \frac{3}{7}  \times  \frac{2}{5} ) - x =  \frac{ - 4}{35}

➺\: \frac{6}{35}  - x =  \frac{ - 4}{35}

➺\:  - x =    \frac{ - 4}{35}  -  \frac{6}{35}

➺\:  - x =  \frac{ - 4 - 6}{35}

➺\:  - x =  \frac{ - 10}{35}

➺\: x =  \frac{2}{7}

Therefore, \frac{2}{7} should be subtracted from the product of \frac{3}{7} and \frac{2}{5} to get \frac{ - 4}{35}.

\large\mathfrak{{\pmb{\underline{\orange{To\:verify}}{\orange{:}}}}}

\: ( \frac{3}{7}  \times  \frac{2}{5} ) - x =  \frac{ - 4}{35}

➼\: ( \frac{6}{35} ) -  \frac{2}{7}  =  \frac{ - 4}{35}

➼\:  \frac{6}{35}  -  \frac{2 \times 5}{7 \times 5}  =  \frac{ - 4}{35}

➼\:  \frac{6 - 10}{35}  =  \frac{ - 4}{35}

➼\:  \frac{ - 4}{35}  =  \frac{ - 4}{35}

➼\: L.H.S.=R. H. S

\sf\purple{Hence\:verified. }

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