Answer:
Part A: 1 solution
Part B:
3(2x-7)=3
6x-21=3
+21 +21
6x=24
/6 /6
x=4
Step-by-step explanation:
First you <u>distribute 3(2x-7)=3</u> to 6x-21=3. Next you do inverse operations by <u>adding 21 to both sides</u> of the equation to get 6x=24. Finally you <u>divide both sides by 6</u> to get x=4
0 m30 kg15 s-30 K-15
that should be the answer
15a⁴b²-20a³b³+30a²b⁴
3a²-4ab+6b²
so for 5a²b²
(5a²b²)(3a²-4ab+6b²)
=15a⁴b²-20a³b³+30a²b⁴