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Orlov [11]
3 years ago
5

[f-g] (3) for f(x)=4x+3 and g(x)=8/x+2 step by step!

Mathematics
1 answer:
gladu [14]3 years ago
6 0

Answer:

10.4

Step-by-step explanation:

x=3⇒f(3)= 4×3+3=15

x=3⇒g(3)=8/3+2≈4.6

f(3)-g(3)=15-4.6=10.4

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Need help from 7-9 pls
expeople1 [14]

Answer:

b 5 a 6 b 7

Step-by-step explanation:

5 0
3 years ago
The Students' Union needs to order some pens and notebooks. How much does it cost to order 1000 pens and 2000 notebooks? $ Cost
NeX [460]

Answer:

Then, it costs $2120 to order 1000 pens and 2000 notebooks.

Step-by-step explanation:

The Students' Union needs to order 1000 pens and 2000 notebooks. The price per pen when buying 1000 of them is 60c. The price per notebook when buying 2000 of them is 76c.

Then the total of money needed to order 1000 pens and 2000 notebooks is:

Total Money = 1000 × 0.60 + 2000 × 0.76 = $2120

Then, it costs $2120 to order 1000 pens and 2000 notebooks.

6 0
3 years ago
What is the perimeter of this shape?
Korvikt [17]

Answer:

59.4 km

Step-by-step explanation:

First you need to find the circumference of the circle. 20*3.14=62.8. Then, you divide this by two, because there is only half of a circle, to get 31.4.

Then you can just add 16 + 12 + 31.4 to get 59.4.

6 0
3 years ago
I need help.. i really want to go sleep.. thank you so much...
Effectus [21]

Answer:

1) True 2) False

Step-by-step explanation:

1) Given  \sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}

To verify that the above equality is true or false:

Now find \sum\limits_{k=0}^8\frac{1}{k+3}

Expanding the summation we get

\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{0+3}+\frac{1}{1+3}+\frac{1}{2+3}+\frac{1}{3+3}+\frac{1}{4+3}+\frac{1}{5+3}+\frac{1}{6+3}+\frac{1}{7+3}+\frac{1}{8+3} \sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}

Now find \sum\limits_{i=3}^{11}\frac{1}{i}

Expanding the summation we get

\sum\limits_{i=3}^{11}\frac{1}{i}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}

 Comparing the two series  we get,

\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i} so the given equality is true.

2) Given \sum\limits_{k=0}^4\frac{3k+3}{k+6}=\sum\limits_{i=1}^3\frac{3i}{i+5}

Verify the above equality is true or false

Now find \sum\limits_{k=0}^4\frac{3k+3}{k+6}

Expanding the summation we get

\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3(0)+3}{0+6}+\frac{3(1)+3}{1+6}+\frac{3(2)+3}{2+6}+\frac{3(3)+4}{3+6}+\frac{3(4)+3}{4+6}

\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}+\frac{12}{8}+\frac{15}{10}

now find \sum\limits_{i=1}^3\frac{3i}{i+5}

Expanding the summation we get

\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3(0)}{0+5}+\frac{3(1)}{1+5}+\frac{3(2)}{2+5}+\frac{3(3)}{3+5}

\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}

Comparing the series we get that the given equality is false.

ie, \sum\limits_{k=0}^4\frac{3k+3}{k+6}\neq\sum\limits_{i=1}^3\frac{3i}{i+5}

6 0
3 years ago
2. At the mall, Leona bought a T-shirt and a book for a total of $23. The book cost $12. How much did the T-shirt cost?
enyata [817]
11 because you have to add from 12 to get to 23
7 0
3 years ago
Read 2 more answers
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