Which best describes the intersection of a pyramid and a plane parallel to one face of the pyramid that is not the base?

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

kherson [118]

Answer:

The answer is

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

Step-by-step explanation:

Remember that Taylor says that

$f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }$

For this case

$f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18$

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

5 0

3 years ago

Find the values of x and y for which the lines are parallel.

bearhunter [10]

The answer: " x = 68, y = 72 " .
____________________________
Explanation:
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46 + (x - 3) + (y - 3) = 180 .

46 + 1(x - 3) + 1(y-3) = 180 .

46 + 1x - 3 + 1y - 3 = 180 .

46 - 3 - 3 + 1x + 1y = 180 .

40 + x + y = 180 ;

Subtract "40" from EACH SIDE of the equation:
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40 + x + y - 40 = 180 - 40 ;

to get:

x + y = 140 ;
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Now:
_____________________________________
65 = (x - 3) ;

↔ x - 3 = 65 ;

Add "3" to EACH SIDE of the equation;

    x - 3 + 3 = 65 + 3 ;

to get:

           x = 68 .
______________________________
Now:

Since: "x + y = 140" ;

Let us plug in our known value, "68" ; for "x" ;

to solve for "y" ;
__________________________________
   x + y = 140 ;

  68 + y = 140 ;

↔ y + 68 = 140 ;

Subtract "68" from EACH SIDE of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;
______________________________________________
   y + 68 - 68 = 140 = 68 ;

                  y = 72 .
______________________________________________
So, solve for "x" and "y".

x = 68, y = 72 .
_______________________________________________

5 0

3 years ago

PLS HELPP! ITS TIMED

Maru [420]

Answer:

Neg will be on 2nd one

Pos will be on 3rd one

Unde will be on 4th one

Zero will be one 1st one

7 0

2 years ago

HELP ASAP- I would give 40 points just for these 3 answers

Slav-nsk [51]

5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.

Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.

6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.

8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.

7 0

3 years ago

Which ratio can be used to form a proportion with the given ratio? 3 to 4

quester [9]

As soon as I see the word "Which ...", I know that there's a list of choices that
goes along with this question, but you decided not to share them. So there's
no way for me to help you choose the correct one.

In order to form a proportion with 3/4, you need another fraction (or ratio) that's
equal to 3/4 . Look for a fraction whose numerator is 3/4 of its denominator.

Here are a few examples:

-- 6 / 8
-- 24 / 32
-- 300 / 400
-- 12 million / 16 million
-- 3x / 4x
-- 15abc / 20abc
-- 3(x+y+z) / 4(x+y+z)

6 0

3 years ago