Answer:
the maximum concentration of the antibiotic during the first 12 hours is 1.185 
at t= 2 hours.
Step-by-step explanation:
We are given the following information:
After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in
Thus, we are given the time interval [0,12] for t.
- We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
- The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.
First, we differentiate C(t) with respect to t, to get,
Equating the first derivative to zero, we get,
Solving, we get,
At t = 0
At t = 2
At t = 12
Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 at t= 2 hours.
Answer:
Step-by-step explanation:
write the equation
Transfer 4.44 to other side and it's sign changes from positive to negative
After subtracting we will get result as 4.44
Arrange the equation as variable always comes at left side.
open brakets
transfer 7 to other side and it changes from - to + sign
Answer:
5km costs $4
if you take the intial charge of $2, you're paying $4 per 5km
hence 10km= 2 *5km= 2*$4=$8+initial charge $2= $10
15Km= 3*5km= 3*$4= $12 + intial charge $2 = $14
Step-by-step explanation:
Properties of Logs
logb(x/y) = log<span>bx</span> - log<span>by</span>.
therefore
log5 (4/7)= log5 (4)- log5 (7)
<span>Solve log 5 (4) and log 5 (7) with the base change of the logarithm</span>
<span>log 5 4 = log 4 / log 5 </span>
Use the calculator:
<span>
<span>log 5 4 =0.8613531161
</span></span>
log 5 7 = log 7 / log 5
<span>log 5 7 =1.2090619551</span>
<span>log5 (4/7)= log5
(4)- log5 (7)=-0.347708839</span>
