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NNADVOKAT [17]
3 years ago
7

Question 5 Now take a look at the angle measurements of AABC and AA'B'C'. Move the slider, and observe the values of the angle m

easurements of the image and the preimage. Measure and record at least two sets of angle measurements in the table. Choose one set of measurements where n> 1 and one set where n< 1. Round the values to the nearest degree. Plato

Mathematics
1 answer:
jeka57 [31]3 years ago
7 0

Answer:

Step-by-step explanation:

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B) State a valid formula for multiplying out (A + B)(A − B)
Diano4ka-milaya [45]

(A+B)(A-B) = A^2-B^2.

It's equality constant

8 0
3 years ago
X and y intercepts g(x)=9x-10
anygoal [31]

the y intercept is -10

the x intercept is

0=9x-10

10=9x

x=10/9

6 0
3 years ago
Read 2 more answers
Given: y" - 2y' = 6t + 5e^2t. Find the correct form to use for y_p if the equation is solved using Undetermined coefficients. Do
const2013 [10]

Answer:

y_p=A+Bt+Ce^{2t}

Step-by-step explanation:

Given: y'' - 2y' = 6t + 5e^{2t}.

we need to find the correct form for y_p if the equation is solve using undetermined coefficients.

A first order differential equation \frac{\mathrm{d} y}{\mathrm{d} x}=f\left ( x,y \right ) is said to be homogeneous if f(tx,ty)=f(x,y) for all t.

Consider homogeneous equation y''-2y'=0

Let y=e^{rt} be the solution .

We get (r^2-2r)e^{rt}=0

Since e^{rt}\neq 0, r^2-2r=0.

So, we get solution as y_c=c_1+c_2e^{2t}

As constant term and e^{2t} are already in the R.H.S of equation

y" - 2y' = 6t + 5e^{2t}, we can take y_p as y_p=A+Bt+Ce^{2t}

6 0
3 years ago
Can you help me with this?
horsena [70]

Answer:

B

Step-by-step explanation:

it this answer

7 0
3 years ago
The average temperature of the week is 80 degrees. The first 3 days have an average of 78 and the average of the last 3 days is
Tju [1.3M]

Answer:

80

Step-by-step explanation:Solution:

step 1 Address the formula, input parameters & values.

Input parameters & values:

The given numbers are 78 & 80

step 2 Find the sum of the given two numbers.

sum = 78 + 80 = 158

step 3 Divide the sum by 2 to get the average.

average = 158/2

= 79

Thus, 79 is an average of positive integers 78 and 80.

3 0
3 years ago
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