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stepladder [879]
3 years ago
13

PLEASE HELP! :D Triangle ABC has vertices A(0,6) B(4,6) C(1,3). Sketch a graph of ABC and use it to find the orthocenter of ABC.

Then list the steps you took to find the orthocenter, including any necessary points or slope you had to derive.
(I know the exact answer. I know the slopes and the point slope form, but I am basically having trouble with the plotting out the altitudes from the given points. Massive brain fart...)
Mathematics
1 answer:
OverLord2011 [107]3 years ago
6 0
I'm pretty sure you can just use a Cartesian plane and since all of your points are (positive, positive) they'd all be in the First Quadrant (top right)
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<span><span>The correct answers are:
</span><span>(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

</span><span>Explanation:
</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = </span></span>\frac{10}{x}<span>

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = </span>\frac{10}{x}<span>

We can write it as:

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If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
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