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stepladder [879]
3 years ago
13

PLEASE HELP! :D Triangle ABC has vertices A(0,6) B(4,6) C(1,3). Sketch a graph of ABC and use it to find the orthocenter of ABC.

Then list the steps you took to find the orthocenter, including any necessary points or slope you had to derive.
(I know the exact answer. I know the slopes and the point slope form, but I am basically having trouble with the plotting out the altitudes from the given points. Massive brain fart...)
Mathematics
1 answer:
OverLord2011 [107]3 years ago
6 0
I'm pretty sure you can just use a Cartesian plane and since all of your points are (positive, positive) they'd all be in the First Quadrant (top right)
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LIKE I ACTUALLY NEED HELP THIS IS LITERAL TESTING NOT NO QUIZ.
Mekhanik [1.2K]

Answer:

2 because if x=0 y=1 and 2 is closest so a and b

4 0
3 years ago
The two-dimensional net of a rectangular prism is shown at the left. What is the prism’s surface area? square units
Tasya [4]

Answer:

28 units²  

Step-by-step explanation:

Assume that your net has the dimensions shown below.

Its area is

2 yellow rectangles = 2(4 × 2) = 2 × 8 = 16 units²

2 grey rectangles    =  2(4 × 1) = 2 × 4  =  8 units²

2 green rectangles  = 2(2 × 1)  = 2 × 2  = <u> 4 units²</u>

                                                 TOTAL = 28 units²

The prism's surface area is 28 units².

5 0
3 years ago
Read 2 more answers
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s.
Harman [31]
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:
0=-16 t^{2} +122t+99
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
-99=-16 t^{2} +122t+99
-16 t^{2} +122+198=0

Now we can apply the quadratic formula t= \frac{-b+or- \sqrt{ b^{2} -4ac} }{2a} where a=-16, b=122, and c=198
t= \frac{-122+or- \sqrt{ 122^{2}-(4)(-16)(198) } }{(2)(-16)}
t= \frac{-122+ \sqrt{27556} }{-32} or t= \frac{-122- \sqrt{27556} }{-32}
t= \frac{-122+166}{-32} or t= \frac{-122-166}{-32}
t= \frac{-11}{8} or t=9

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
5 0
3 years ago
Read 2 more answers
The measure of angle A is 15°, and the length of side
dangina [55]

Answer:

Part 1) AB=30.9\ units

Part 2) AC=29.9\ units

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

sin(A)=\frac{BC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

sin(15^o)=\frac{8}{AB}

solve for AB

AB=\frac{8}{sin(15^o)}=30.9\ units

Part 2

Find the length side AC

we know that

tan(A)=\frac{BC}{AC} ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

tan(15^o)=\frac{8}{AC}

solve for AC

AC=\frac{8}{tan(15^o)}=29.9\ units

8 0
3 years ago
Which statement is true about the polynomial
Ghella [55]

Answer:3 terms and a degree of 9

Step-by-step explanation:

7 0
3 years ago
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