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3 years ago

Solve each equation for m. Then find the value of m for each value of n.

Mathematics

1 answer:

Misha Larkins [42]3 years ago

5 0

If n = –2, then m is equal to 13;

If n = 0, then m is equal to 7;

If n = 1, then m is equal to 4

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(Round to the nearest tenth of a percent.) In 2011, the IRS increased the deductible mileage cost to

RUDIKE [14]

Answer:

$\%Change = 8.8\%$

Step-by-step explanation:

Given

$Initial = 51\ cents$

$Final = 55.5\ cents$

Required

Determine the percentage change

Percentage change is calculated as;

$\%Change = \frac{Final - Initial}{Initial} * 100\%$

$\%Change = \frac{55.5 - 51 }{51 } * 100\%$

$\%Change = \frac{4.5}{51} * 100\%$

$\%Change = \frac{4.5* 100\%}{51}$

$\%Change = \frac{450\%}{51}$

$\%Change = 8.8\%$

<em>Hence, the percentage change is approximately 8.8%</em>

6 0

2 years ago

Im need help on this question

dimulka [17.4K]

You were right, its the second choice CA=CB+BA

4 0

3 years ago

A ball is thrown up in the air from 5 feet above the ground level. The ball reached a height of an additional 6 feet in approxim

Musya8 [376]

Answer:it’s F

Step-by-step explanation:

It’s F

6 0

3 years ago

www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb

damaskus [11]

Answer:

$z=\frac{24-40}{8}=-2$

$z=\frac{40-40}{8}=0$

And then the percentage between 24 and 40 would be $\frac{95}{2}= 47.5 \%$

Step-by-step explanation:

For this problem we have the following parameters given:

$\mu = 40, \sigma =8$

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

$z=\frac{X-\mu}{\sigma}$

And replacing we got:

$z=\frac{24-40}{8}=-2$

$z=\frac{40-40}{8}=0$

And then the percentage between 24 and 40 would be $\frac{95}{2}= 47.5 \%$

5 0

3 years ago

Evaluate the expression for the given value of the variable -4b-8 + -1 b^2 + 2b^3 ; b= -2

Bad White [126]

-4b-8 + -1b^2 +2b^3
-4(-2)-8+-1(-2)^2+2(-2)^3
8-8+2^2-4^3
4-64
60

4 0

3 years ago

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