Question

PLEASE HELP ME: Find the perimeter of the figure. Round to the nearest tenth.

Answer 1

Answer:

perimeter = 20.9 units

Step-by-step explanation:

perimeter

perimeter = distance around two dimensional shape

= addition of all sides lengths

perimeter of the figure

= AB+BC+CD+AD

distance formula:

$d = \sqrt{( x_{2} - x_{1}) {}^{2} + ( y_{2} - y_{1}) {}^{2} }$

1) distance of AB

A(-3,0) B(2,4)

x1 = -3 x2 = 2

y1 = 0 y2 = 4

(substitute the values into the distance formula)

$ab = \sqrt{(2 - ( - 3)) {}^{2} + (4 - 0) {}^{2} }$

$ab = \sqrt{5 {}^{2} + 4 {}^{2} }$

$ab = \sqrt{41}$AB = 6.4 units

2) distance of BC

B(2,4) C(3,1)

x1 = 2 x2 = 3

y1 = 4 y2 = 1

$bc = \sqrt{(3 - 2) {}^{2} + (1 - 4) {}^{2} }$

$bc = \sqrt{1 {}^{2} + ( - 3) {}^{2} }$

$bc = \sqrt{10}$

BC = 3.2 units

3) distance of CD

C(3,1) D(-4,-3)

x1 = 3 x2 = -4

y1 = 1 y2 = -3

$cd = \sqrt{( - 4 - 3) {}^{2} + ( - 3 - 1)) {}^{2} }$

$cd = \sqrt{( - 7) {}^{2} + ( - 4 ){}^{2} }$

$cd = \sqrt{65}$

CD = 8.1 units

4) distance of AD

A(-3,0) D(-4,-3)

x1 = -3 x2 = -4

y1 = 0 y2 = -3

$ad = \sqrt{( - 4 - ( - 3)) {}^{2} + ( - 3 - 0) {}^{2} }$

$ad = \sqrt{( - 1) {}^{2} + ( - 3) {}^{2} }$

$ad = \sqrt{10}$

AD = 3.2 units

perimeter of figure

= AB+BC+CD+AD

= 6.4 + 3.2 + 8.1 + 3.2

= 20.9 units