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V125BC [204]
4 years ago
6

A person stands 303030 meters east of an intersection and watches a car driving away from the intersection to the north at 17171

7 meters per second. At a certain instant, the car is 161616 meters from the intersection. What is the rate of change of the distance between the car and the person at that instant (in meters per second)?
Mathematics
1 answer:
DanielleElmas [232]4 years ago
5 0

Answer:

Step-by-step explanation:

If you do 303030-161616+171717= 313131

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Simplify.<br> 4(w-2) - 6
Alex Ar [27]
Answer: 4w-14

Step By step explanation: 4(w-2)-6= 4w-8-6= 4w-14
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4 years ago
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What is 3.30 divided by -2.00? Show work.
coldgirl [10]

Answer:

<h2>1.65</h2>

Step-by-step explanation:

\frac{3.3}{-2}\\\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}\\=-\frac{3.3}{2}\\\\\mathrm{Divide\:the\:numbers:}\:\\\frac{3.3}{2}=1.65

7 0
3 years ago
The cost for a company to produce x t-shirts can be modeled by
lana [24]

Answer:

P(x)=-2x^2+34x+98

The cost function is given by c(x)=21x-98

And the revenue function is given by  r(x)=55x-2x^2

The profit function is the difference of revenue function and the cost function. Mathematically, we can write

p(x)=r(x)-c(x)

Substituting the values, we get

p(x)=55x-2x^2-(21x-98)

p(x)=-2x^2 + 34x = 98

Therefore, the profit function is

p(x) = -2x^2 + 34x + 98

Step-by-step explanation:

6 0
4 years ago
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Suppose I make several time measurements, and compute an average time of 3.4 s, with a standard deviation of 0.8 s and an SDOM o
7nadin3 [17]

Answer:

The result will be smaller than 2.6s, 16% of the time.

Step-by-step explanation:

This is a normal distribution problem

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - xbar)/σ

x = the random value = 2.6 s

xbar = mean = the average = 3.4 s

σ = standard deviation = 0.8 s

z = (2.6 - 3.4)/0.8 = - 1

P(x < 2.6) = P(z < - 1) = 1 - P(z ≥ - 1) = 1 - P(z ≤ 1) = 1 - 0.841 = 0.159 = 16%

8 0
3 years ago
Points S,U, and T are the midpoints of the sides of PQR. Which statements are correct ? 1/2QP=UT 1/2TS=RQ SU=PR SU||RP UT=RP
cricket20 [7]

Answer:

\frac{1}{2} QP = UT

Step-by-step explanation:

GIVEN : In ΔPQR

              S is the mid point of QP

              U is the mid point of PR

              T is the mid point of  QR

Solution :

i) is true i.e \frac{1}{2} QP = UT

Refer the attached file

By mid segment theorem i.e. In a triangle, the line joining the midpoints of any two sides will be parallel to the third side and that same line joining the midpoints is also half of length of third side .

UT is the line joining the two mid points . So, by theorem given above UT is parallel to PQ and  1/2QP=UT.

So, (i) statement is true i.e. \frac{1}{2} QP = UT

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3 years ago
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