Question

A wheel, which is part of a game at a shopping center is arranged to give 2 tickets 50% of the time, 5 tickets 25% of the time, 10 tickets 23% of the time, and 10 tickets 2% of the time. A player enters the shopping center and spins the wheel. Calculate the expected number of tickets he will get.

Answer 1

Answer:

The expected number of tickets a customer will get is 4.75.

Step-by-step explanation:

The probability distribution of the number of ticket a wheel at a shopping center is arranged to give is as follows:

X           Probability (p)

2                  0.50

5                  0.25

10                  0.23

10                  0.02

The formula to compute the expected value of a random variable is:

$E(X)=\sum x\cdot P (X=x)$

Compute the expected number of tickets a customer will get as follows:

$E(X)=\sum x\cdot P (X=x)$

         $=(2\times 0.50)+(5\times 0.25)+(10\times 0.23)+(10\times 0.02)\\=1+1.25+2.3+0.2\\=4.75$

Thus, the expected number of tickets a customer will get is 4.75.