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shtirl [24]
3 years ago
8

Suppose I make several time measurements, and compute an average time of 3.4 s, with a standard deviation of 0.8 s and an SDOM o

f 0.2 s. If I make another time measurement, how often would I expect the result to be smaller than 2.6s\
Mathematics
1 answer:
7nadin3 [17]3 years ago
8 0

Answer:

The result will be smaller than 2.6s, 16% of the time.

Step-by-step explanation:

This is a normal distribution problem

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - xbar)/σ

x = the random value = 2.6 s

xbar = mean = the average = 3.4 s

σ = standard deviation = 0.8 s

z = (2.6 - 3.4)/0.8 = - 1

P(x < 2.6) = P(z < - 1) = 1 - P(z ≥ - 1) = 1 - P(z ≤ 1) = 1 - 0.841 = 0.159 = 16%

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Answer:

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Step-by-step explanation:

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(\frac{6*7+5*-1}{11} ,\frac{6*7+5*7}{11} )

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