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yaroslaw [1]
4 years ago
9

-3(x + 6) = Simplify expression

Mathematics
2 answers:
omeli [17]4 years ago
5 0

Answer:

3x +18

Step-by-step explanation:

use distributive property.

VMariaS [17]4 years ago
3 0

Answer:

x=-6

Step-by-step explanation:

1.) Distribute the -3

-3x - 18

2.) Set the equation equal to zero and add 18 on both sides

-3x-18=0

-3x=18

3.) Divide both sides by -3

x=-6

Negative 6 is equivalent to X

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HELP. Need help on this
pishuonlain [190]

Answer:

what are the answers

Step-by-step explanation:

3 0
3 years ago
Solve 5 2/15 a =3 2/25
vovikov84 [41]

Answer:

a= 3/5

decimal form: 0.6

Step-by-step explanation:

4 0
3 years ago
In order to ride a roller coaster,a rider must be greater than 49 inches tall.Right now,Jeff is 45 inches tall.Write an inequali
WARRIOR [948]

Answer:

Therefore, we conclude that the Jeff must grow 4 inches in order to ride the roller-coaster.

Step-by-step explanation:

We know that: in order to ride a roller coaster,a rider must be greater than 49 inches tall.Jeff is 45 inches tall.

We have the next  inequalitythats:

x+45>49\\\\x>49-45\\\\x>4\\

Therefore, we conclude that the Jeff must grow  4 inches in order to ride the roller-coaster.

4 0
4 years ago
Trigonometry
Mashcka [7]

The area of the triangle EFG is 7.4 square units.

Explanation:

Given that the measurements of the sides of the triangle are EF = 8, EG = 8 and m\angle E=22^{\circ}

We need to determine the area of the triangle EFG

<u>Area of the triangle:</u>

The area of the triangle EFG can be determined using the formula,

\text {Area}=\frac{1}{2} fg \sin E

Substituting the values, we get,

\text {Area}=\frac{1}{2} (5)(8) \sin 22^{\circ}

Simplifying the values, we have,

\text {Area}=\frac{1}{2}(40)(0.37)

Multiplying, we get,

\text {Area}=\frac{14.8}{2}

Dividing, we get,

\text {Area}=7.4

Hence, the area of the triangle EFG is 7.4 square units.

3 0
3 years ago
What is the common difference for the sequence shown below?
Nezavi [6.7K]

we can always find the slope of any line by simply using two points on the line, say let's  use (3,4) and (-1,2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-4}{-1-3}\implies \cfrac{-2}{-4}\implies \stackrel{\stackrel{\textit{common difference}}{\downarrow }}{\cfrac{1}{2}}

5 0
3 years ago
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