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3 years ago

Can someone help me please

Mathematics

1 answer:

m_a_m_a [10]3 years ago

3 0

. In short is song/song = hour/hour that gives 15/2.5 = 18/h

This proportion also could be written as : 2.5/15 = h/18

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WHO WANTS TO PLAY TRUTH OR DARE?????!!!!!

babunello [35]

Answer:

I am in for the game......

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2 years ago

Read 2 more answers

The shampoo you like to use is on sale. But you only get the lower price if you buy 3 bottles...?

meriva

The sale price of 3 bottles of shampoo is 3s and the regular price is 3r. The amount of money you save will only come in when you buy 3. The cost you save is the difference between the regular price and the sale price. The equation is therefore,
c = 3r - 3s

8 0

3 years ago

Write the equation of the given circle.<br><br> center (1, -5)<br> radius of 10

Naddika [18.5K]

Answer:

$(x-1)^2+(y+5)^2=100$

Step-by-step explanation:

The equation of a circle has the following form:

$(x-h)^2+(y-k)^2=r^2$ where (h,k) is the center of a circle with radius r.

Our equation center is (1.-5) and radius is 10.

$(x-1)^2+(y--5)^2=10^2$

$(x-1)^2+(y+5)^2=100$

3 0

3 years ago

Find the volume v of the described solid s. the base of s is an elliptical region with boundary curve 4x2 + 9y2 = 36. cross-sect

Tasya [4]

$4x^2+9y^2=36\iff\dfrac{x^2}9+\dfrac{y^2}4=1$

defines an ellipse centered at $(0,0)$ with semi-major axis length 3 and semi-minor axis length 2. The semi-major axis lies on the $x$ -axis. So if cross sections are taken perpendicular to the $x$ -axis, any such triangular section will have a base that is determined by the vertical distance between the lower and upper halves of the ellipse. That is, any cross section taken at $x=x_0$ will have a base of length

$\dfrac{x^2}9+\dfrac{y^2}4=1\implies y=\pm\dfrac23\sqrt{9-x^2}$
$\implies \text{base}=\dfrac23\sqrt{9-{x_0}^2}-\left(-\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac43\sqrt{9-{x_0}^2}$

I've attached a graphic of what a sample section would look like.

Any such isosceles triangle will have a hypotenuse that occurs in a $\sqrt2:1$ ratio with either of the remaining legs. So if the hypotenuse is $\dfrac43\sqrt{9-{x_0}^2}$ , then either leg will have length $\dfrac4{3\sqrt2}\sqrt{9-{x_0}^2}$ .

Now the legs form a similar triangle with the height of the triangle, where the legs of the larger triangle section are the hypotenuses and the height is one of the legs. This means the height of the triangular section is $\dfrac4{3(\sqrt2)^2}\sqrt{9-{x_0}^2}=\dfrac23\sqrt{9-{x_0}^2}$ .

Finally, $x_0$ can be chosen from any value in $-3\le x_0\le3$ . We're now ready to set up the integral to find the volume of the solid. The volume is the sum of the infinitely many triangular sections' areas, which are

$\dfrac12\left(\dfrac43\sqrt{9-{x_0}^2}\right)\left(\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac49(9-{x_0}^2)$

and so the volume would be

$\displaystyle\int_{x=-3}^{x=3}\frac49(9-x^2)\,\mathrm dx$
$=\left(4x-\dfrac4{27}x^3\right)\bigg|_{x=-3}^{x=3}$
$=16$

6 0

3 years ago

lutik1710 [3]

Answer:

D. $0, $20, $90

Step-by-step explanation:

If X represents the amount you win, then possible outcomes for X are $0, $20, and $90.

4 0

4 years ago