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Fittoniya [83]
3 years ago
15

Please help this is in my test tomorrow♡

Mathematics
1 answer:
MAVERICK [17]3 years ago
5 0

Answer:

<u><em>67</em></u>

Step-by-step explanation:

<u><em>50-40+87-30</em></u>

=50+(- 40)+87(-30)

=50+87+(-40)+(-30)

=(50+87+(-40)+(-30)

=137+(-70)

=67

<u><em></em></u>

<u><em></em></u>

<u><em></em></u>

<u><em>when he wins, we add points. When he loses ,we subtract points.The score is 50 points. We right  an expression to find the final score </em></u>

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If 4w - 1 = 11, then 4w = 12<br> what is the property?
KonstantinChe [14]

Answer:

Addition property of equality.

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3 years ago
How many 330ml bottles could you completely fill with 4 litres of water
Neko [114]

Answer:

12.1212-repeating

Step-by-step explanation:

Milliliters are 1000 times smaller (Larger in number, smaller in size). So when you calculate 4 liters times 1000, you would get 4000 milliliters. Then you would divide the 4000 by 330, and then you would get 12.121212-Repeating decimal.

7 0
2 years ago
75/5-(4-1)^2. PLZZZZ ANSWER THIS
tia_tia [17]
75/5-(4-1)^2

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15-(4-1)^2

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3 0
3 years ago
3 x 2/5 Multiplying Fractions
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Step-by-step explanation:

3 0
2 years ago
A sample of 12 radon detectors of a certain type was selected, and each was exposed to 100 pCI/L of radon. The resulting reading
valkas [14]

Answer:

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

p_v =2*P(t_{11}  

Step-by-step explanation:

1) Data given and notation  

Data: 105.6, 90.9, 91.2, 96.9, 96.5, 91.3, 100.1, 105.0, 99.6, 107.7, 103.3, 92.4

We can calculate the sample mean and deviation for this data with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

The results obtained are:

\bar X=98.375 represent the sample mean  

s=0.6.109 represent the sample standard deviation  

n=12 sample size  

\mu_o =100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 100pCL/L, the system of hypothesis are :  

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

4) P-value  

First we need to find the degrees of freedom for the statistic given by:

df=n-1=12-1=11

Since is a two sided test the p value would given by:  

p_v =2*P(t_{11}  

5) Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significant different from 100 at 5% of significance.  

3 0
3 years ago
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