Answer:
Afternoon class has more students.
Step-by-step explanation:
Let m be the number of students in the morning class and n be the number of students in the afternoon class.
The average score for the students in the morning class was 80, then the sum of their scores is 
The average score for the students in the afternoon class was 86, then the sum of their scores is 
The sum of the scores of both classes is
and the average score is
The average (arithmetic mean) score for the two classes combined was 84, then
This means n is greater, so afternoon class has more students.
First we can simplify f(x) to make it a little easier. We can write it as
4x^3+2x^2-7x+4 by combining like terms
The we just subtract g(x) from f(x) and simplify
4x^3+2x^2-7x+4-(5x^3-7x+4) and remember to distribute the negative to g(x)
4x^3+2x^2-7x+4-5x^3+7x-4 (combine like terms)
-x^3+2x^2
In factored form, this becomes
-x^2(x-2)
Hope this helps
Answer: 1
Step-by-step explanation:
5+13/18
18/18
1
Answer:
Step-by-step explanation:
za/2: Divide the confidence interval by two, and look that area up in the z-table: .95 / 2 = 0.475. ...
E (margin of error): Divide the given width by 2. 6% / 2. ...
: use the given percentage. 41% = 0.41. ...
: subtract. from 1.
Answer: Hope this helps!
Left to right - Q1 - Q5
1,500, 1,250, 0.25, 105, 25%
Step-by-step explanation:
Q1 - 15,000 * 0.02 * 5 = 1,500
Q2 - 25,000 * 0.01 * 5 = 1,250
Q3 - 20 - ((6 * 1) + (3 * 0.75) + (10 * 0.35) + (4 * 2)) = 0.25, 25 cents
Q4 - 30x + 1,000 = 4,200 (X = 107) Approximately 105 jobs
Q5 - 1,584 / (32 * 66) = 0.75 (75%) 100% - 75% = 25%
