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3 years ago

14

An air-track glider attached to a spring oscillates between the 13.0 cm mark and the 65.0 cm mark on the track. The glider compl

etes 14.0 oscillations in 35.0 s . What are the (a) period, (b) frequency, (c) amplitude, and (d) maximum speed of the glider?

1 answer:

Serggg [28]3 years ago

8 0

Answer:

Time period = 2.5 sec

Frequency = 0.4 Hz

Amplitude = 0.26 m

Maximum speed = 0.65 $\frac{m}{s}$

Explanation:

No. of oscillations = 14

Time = 35 sec

(a). Time period of oscillation

$T = \frac{35}{14}$

T = 2.5 sec

This is the time period.

(b). Frequency

$f = \frac{1}{T}$

$f = \frac{1}{2.5}$

f = 0.4 Hz

This is the frequency.

(c). Oscillation from one side to another side is 65 - 13 = 52 cm = 0.52 m

Hence amplitude

$A = \frac{1}{2} (0.52)$

A = 0.26 m

This is the amplitude.

(d). The maximum speed

$v_{max} = (2 \pi f) A$

$v_{max} =$ 2 × 3.14 × 0.4 × 0.26

$v_{max} =$ 0.65 $\frac{m}{s}$

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