Answer:
i think its C hope this is rhight have a good day
Explanation:
Answer:
a. Ssystem > 40 J/K
Explanation:
Given that
The entropy of first block = 10 J/K
The entropy of second block = 30 J/K
When two bodies come into contact with each other, the entropy of the combined system will increase and the entropy sum remains unchanged: According to the Second law of thermodynamics.The entropy of the system will be greater than 40 J/K.
Therefore the answer is a.
Ssystem > 40 J/K
Answer:
12.5
Explanation:
Pressure: Force/Area = 650/52
=12.5
Answer:
Explanation:
Ignoring friction, the acceleration will double
F = ma
2F = m(2a)
Answer:
A) True, B) False, C) False and D) false
Explanation:
Let's solve the problem using the law of conservation of energy to know if the statements are true or false
Let's look for mechanical energy
Initial
Emo = Ke = ½ k Dx2
Final
Em1= ½ m v12
Emo = Em1
½ k Δx2 = ½ m v₁²
v₁² = k / m Δx²
v₁ = √ k/m Δx
Now let's calculate the speed when it falls
Vfy² = Voy² - 2gy
Vfy² = - 2gy
Vf² = v₁² + vfy²
A) True v₁ = A Δx
.B) False. As there is no rubbing the mechanical energy conserves
.C) False the velocity is proportional to the square root of the height
v2y = v2 √2
. D) false promotional compression speed