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ANTONII [103]
4 years ago
13

PLEASE HELP!

Mathematics
1 answer:
serg [7]4 years ago
3 0

Hello from MrBillDoesMath!

Answer:

x = 30

Discussion:

Note: I ignored the * in f*(x)  as i don't know what it means. (If this is not what you intended, please indicate what * means)

f(x) = 2 sqrt(x-5) + 4          

f(x) = 14

=>

14 = 2 sqrt(x-5) + 4             => subtract 4 from both sides

14 -4 = 2 sqrt(x-5)               => divide both sides by 2

10/2 = sqrt(x-5)                   =>

5 = sqrt(x-5)                        => square both sides

5*5 = x-5                              => add 5 to both sides

5*5 + 5  = x

25 + 5 = x

x = 30

Thank you,

MrB

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Answer:

The expression is n = (\frac{1.645*0.5}{0.03})^2

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

What expression would give the smallest sample size that will result in a margin of error of no more than 3 percentage points?

We have to find n for which M = 0.03.

We have no prior estimate for the proportion, so we use \pi = 0.5. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.645*0.5

\sqrt{n} = \frac{1.645*0.5}{0.03}

(\sqrt{n})^2 = (\frac{1.645*0.5}{0.03})^2

n = (\frac{1.645*0.5}{0.03})^2

The expression is n = (\frac{1.645*0.5}{0.03})^2

3 0
3 years ago
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