We are given with three equations and three unknowns and we need to solve this problem. The solution is shown below:
Three equations are below:
3x + 4y - z = -6
5x + 8y + 2z = 2
-x + y + z = 0
use the first (multiply by +2) and use the second equation:
2 (3x+4y -z = -6) => 6x + 8y -2z = -12
+ ( 5x + 8y +2z = 2)
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11x + 16y = -10 -> this the fourth equation
use the first and third equation:
3x + 4y -z = -6
+ (-x + y + z =0)
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2x + 5y = -6 -> this is the fifth equaiton
use fourth (multiply by 2) and use fifth (multiply by -11) equations such as:
2 (11x + 16y = -10) => 22x + 32y = -20 -> this is the sixth equation
-11 (2x + 5y = -6) => -22x -55y = 46 -> this is the seventh equation
add 6th and 7th equation such as:
22x + 32y = -20
+(-22x - 55y = 66)
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- 23y = 46
<span> y = -2
solving for x, we have:
</span>2x + 5y = -6
2x = -6 - 5y
2x = -6 - (5*(-2))
2x = -6 +10
2x = 4
x=2
solving for y value, we have:
-x + y + z =0
z = x -y
z = 2- (-2)
z =4
The answers are the following:
x = 2
y = -2
z = 4
Let's say p = 3
2(3)^0
Solving that, you'd get 2
C is the only answer that does not equal one
Answer:
what in the world is the first part
Step-by-step explanation:
Ok so I'll show u how to do number 7
So 12 and one third basically equals 12+(1/3)
Now in order to add this to another fraction, we need to make the mixed numbers in improper fractions
So 12 and (1/3)=(36/3)+(1/3)
And 9 and (2/3)=(27/3)+(2/3)
Ok so the first number (or 12 and (1/3)) basically equals (37/3)
The second number (or 9 and (2/3)) equals (29/3)
Now that we have the two numbers with common denominators, we can do the math.
(37/3)-(29/3) is the same as (37-29)/3
So simplifying would be
(8/3) or 2 and (2/3)
Hoped this helped
Answer:
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