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sammy [17]
3 years ago
6

ERROR ANALYSIS In Exercises 31 describe and

Mathematics
1 answer:
Marta_Voda [28]3 years ago
7 0

The student is doing great so far. However, they forgot to take the square root of that result to get the final answer of \sqrt{61}

The exact distance is \sqrt{61} which approximates to roughly 7.81024967590666

----------------------

This is what the steps should look like

AB = \sqrt{ (6-1)^2 + (2-(-4))^2}\\\\AB = \sqrt{ (5)^2 + (6)^2}\\\\AB = \sqrt{ 25 + 36}\\\\AB = \sqrt{ 61} \ \ \text{ Exact distance}\\\\AB \approx 7.81024967590666  \ \ \text{ Approximate distance}\\\\

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Answer:

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Step-by-step explanation:

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Find the width of a rectangle 25 feet and the perimeter is 80​
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\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>a </u><u>rectangle </u><u>with </u><u>length</u><u> </u><u>2</u><u>5</u><u> </u><u>feet </u><u>and </u><u>perimeter </u><u>8</u><u>0</u><u> </u><u>feet</u>

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\bold{Perimeter \: of \: rectangle = 2(l + b)} \\

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‎ ‎ ‎

<u>substituting</u><u> </u><u>the </u><u>values </u><u>in </u><u>the </u><u>formula </u><u>stated </u><u>above </u><u>,</u>

\bold{80  = 2(25 + b)} \\  \\\bold{ \implies \: 25 + b = \cancel \frac{80}{2} } \\  \\ \bold{\implies \: 25 + b = 40 }\\  \\ \bold{\implies \: b = 40 - 25 }\\  \\\bold{ \implies \: b = 15 \: feet}

hope helpful ~

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Try this:
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the answer is 4r+3b

please give me 5 star rating and a thank you if this helped.

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