The last line of a proof represents <span>the conclusion. The correct option among all the options that are given in the question is the third option or the penultimate option. The other choices can be easily neglected. I hope that this is the answer that has actually come to your desired help.</span>
Step-by-step explanation:
Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues
Here, we have

First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.
Since, we don't want x to be 0,
We have a removable discontinuity at x=0
Now, we have

We don't want the denomiator be zero because we can't divide by zero.
so


So our domain is
All Real Numbers except-2 and 0.
The vertical asymptors is x=-2.
To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of
The leading coeffixent of the numerator/ the leading coefficent of the denomiator.
So that becomes

So we have a horinzontal asymptofe of 2
Answer:
TERO BAU KO TAUKO MULA JEPAITE SODCHOS
Answer:
SAS Reflective property
Step-by-step explanation:
Answer:
Step-by-step explanation:
I got you first you want to get some little ceasers