Suppose the term of an investment at simple interest is doubled. does the interest received double?

You charge customers $18.75 for lube service, parts, and labor. Assuming you take one hour's labor at $15, and the parts cost $3

hram777 [196]

Let
T---------> <span>the tax rate on the parts in $

we know that
$18.75=$15+$3.50+$T
T=18.75-15-3.5
T=$0.25
so
$3.50----------> 100%
$0.25--------> x
x=0.25*100/3.50------> x=7.14%------> x=7.1%

the answer is
7.1%</span>

5 0

2 years ago

Exploring Systems of Linear Equations 2x +3y =8 and 3x+y= -2

butalik [34]

The solution of the linear equations will be ( -2, 4).

<h3>What is an equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

Given equations are:-

2x +3y = 8 and 3x+y= -2

Solving the equations by elimination method:-

2x +3y = 8

3x+y= -2

Multiply the second equation by 3 and subtract from the first equation.

2x +3y = 8

-9x -3y = 6

----------------

-7x = 14

x = -2

Out of the value of x in any one equation, we will get the value of y.

3x+y= -2

3 ( -2) + y = -2

-6 + y = -2

y = 4

The graph of the equations is also attached with the answer below.

Therefore the solution of the linear equations will be ( -2, 4).

The complete question is given below:-

Exploring Systems of Linear Equations 2x +3y =8 and 3x+y= -2. Find the value of x and y and draw a graph for the system of linear equations.

To know more about equations follow

brainly.com/question/2972832

#SPJ1

3 0

1 year ago

There are 10 pens in a box. There are x red pens in the box. All the other pens are blue. Jack takes at random two pens from the

expeople1 [14]

The probability that one of each color is selected is $\frac{10x - x^2}{45}$

<h3>Probabilities</h3>

The probability of an event is the chances of the said event

The given parameters are:

Total = 10
Red = x
Blue = 10 - x

<h3>Calculating the required probability</h3>

The probability that one of each color is selected is calculated as follows:

$P = P(Blue) \times P(Red) + P(Red) \times P(Blue)$

So, we have:

$P = \frac{10 - x}{10} \times \frac{x}{9} + \frac{x}{10} \times \frac{10 - x}{9}$

This gives

$P = \frac{x(10 - x)}{90} +\frac{x(10 - x)}{90}$

Take LCM

$P = \frac{2x(10 - x)}{90}$

Simplify the above expression

$P = \frac{x(10 - x)}{45}$

Expand

$P = \frac{10x - x^2}{45}$

Hence, the probability that one of each color is selected is $P = \frac{10x - x^2}{45}$