If you want to check if your answer is correct, expanding it all out will help!
(x-6)(x+2)=0 <-- Use FOIL tactic
x²+2x-6x-12=0
x²-4x-12=0
As you can see, this is identical to the initial equation given. The x values would be 6 and -2, as seen from the factored equation.
Hope I helped :)
The step most likely to follow this is 2x = 25 because you next want to add 5 to both sides.
25 cents 10cents 10cents 1cent 1cent
Answer:
see below
Step-by-step explanation:
1st: x
2nd: 5x + 8
x(5x + 8) = 36
5x² + 8x = 36
5x² + 8x - 36 = 0
(x - 2)(5x + 18) = 0
(x - 2) = 0
x - 2 = 0
x = 2
1st: x = 2
2nd: 5x + 8 = 5(2) + 8 = 18
(5x + 18) = 0
5x + 18 = 0
5x = -18
x = -3.6
1st: x = -3.6
2nd: 5x + 8 = 5(-3.6) + 8 = -18 + 8 = -10
Substitute sin(x) = tan(t) and cos(x) dx = sec²(t) dt. We want this change of variable to be reversible, so let's assume bot x and t are bounded between 0 and π/2.
Then we have
Recall the Pythagorean identity,
1 + tan²(t) = sec²(t)
Then
√(1 + tan²(t)) = √(sec²(t)) = sec(t)
and the integral reduces to
Change the variable back to x, so the antiderivative is
