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lilavasa [31]
3 years ago
14

The mass of Mars is about 6.421x10^20 metric tons. The mass of the sun is about 1.998x10^27 metric tons. About how many times th

e mass of Mars is the mass of the sun? Give your answer in scientific notation.
Mathematics
1 answer:
Brrunno [24]3 years ago
3 0
<span>It's asking, 'How many times would the mass of Mars 'fit into' the mass of the Sun'? Well, the mass of Mars would go into the mass of the Sun.

</span><span><span><span>m(<span>sun)/</span></span><span>m(<span>mars)</span></span></span>=<span><span>1.998×<span>10^27/</span></span><span>6.421×<span>10^20</span></span></span>=3111664.85=3.112×<span>10^6</span></span>
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The four hand of a clock moves from 12 to 5 o'clock through how many degrees does it move?
julsineya [31]
To find the answer you have to first find how many degrees are there in between each number in the clock. the clock is 360°degrees and there are 12 numbers marked in a clock., so you have to divide 360 by 12 to get the number of degrees in between each number,
360°÷12=30° so there are 30°degrees between each number. 

if a clock hand moves from 12 to 5, it pass 5 numbers, so to get your final answer you have to multiply 30° by 5=150°.

so your answer is 150°degrees.
hope you can understand what i said. :)
8 0
3 years ago
If the order of three loci is A B C, and the map distance between A and B is 15 m.u., and the map distance between B and C is 20
zysi [14]

Answer:

Therefore, we conclute that the map distance between A and C is 35 m.u..

Step-by-step explanation:

We know that the order of three loci is A B C, and the map distance between A and B is 15 m.u., and the map distance between B and C is 20 m.u. We calculate the map distance between A and C.

Therefore, we get

AC=AB+BC\\\\AC=15+20\\\\AC=35\\

Therefore, we conclute that the map distance between A and C is 35 m.u..

4 0
3 years ago
What is the factorization of 729^15+1000?
igomit [66]

Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form (a^{3} +b^{3} ) or (a^{3} -b^{3}). It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

1.) We calculate the cubic root of each term in the equation 729x^{15} +1000, and the exponent of the letter x is divided by 3.

\sqrt[3]{729x^{15}} =9x^{5}

1000=10^{3} then \sqrt[3]{10^{3}} =10

So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

<em>Sum of cubes</em>

(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

with a= 9x^{5} y b=10

2.) Solving the sum of cubes.

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

.

8 0
2 years ago
writing to explain what is the greatest six-digit number you can write? what is the smallest six-digit number your can write? dr
musickatia [10]
Biggest is all nine's
smallest is 1 then zeroes


greatest
999999
smallest
10000
4 0
3 years ago
Estimate 3 2/5 to the nearest integer
pickupchik [31]

4 is the nearest integer

as a decimal this number would be 3.5, which would round up to 4.

8 0
2 years ago
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