Answer:
g o f = -[f(x)]² + 3 = -(|x|)² + 3 = -x² + 3 = g(x)
Step-by-step explanation:
g o f = g [ f(x) ]
This means replace the x of g(x) with f(x):
g o f = -[f(x)]² + 3 = -(|x|)² + 3
As x² ≥ 0 for any value of x (whether it be positive or negative), then -(|x|)² + 3 = -x² + 3 = g(x)
So g o f = g(x)
<h3>
Answer: Movie A</h3>
Q3, or third quartile, is visually located at the right edge of the box. Movie A shows to have a smaller Q3 value as it is to the left of Q3 for movie B.
The correct answer is a. for very high x-values, f(x) moves towards positive infinity.
This can always be determined by two factors.
1) is it linear or something else?
2) Is the lead coefficient positive or negative.
In this case, since the x is not being raised to a power or is not raised to a power itself, we know that there are no asymptotes. That takes care of #1 for us.
As for #2, since the coefficient of x (which is the highest power here) is positive, that means it continues to get bigger. If it were negative it would be the opposite. So, the correct answer is that as x gets bigger, f(x) moves towards positive infinity.
Chain rule:
if
y=y(u) and u=u(x)
The dy/dx=(dv/du)(du/dx)
In our case
y=arcsin(u)
u=sin(x)
dy/du=1/√(1-u²) = 1/√(1-sin²x)
du/dx=cos x
dy/dx=cos x /√(1-sin²x)
Answer: dy/dx=cos x /√(1-sin²x)
If the rounding is to the nearest ten, then the greatest one
is 67,404 and the smallest one is 67,395 .
If the rounding is to the nearest hundred, then the greatest one
is 67,449 and the smallest one is 67,950 .
