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AveGali [126]
3 years ago
5

Using chain rule, what is the derivative of arcsin(sin(x))

Mathematics
1 answer:
oee [108]3 years ago
7 0
Chain rule:
if
y=y(u) and u=u(x)
The dy/dx=(dv/du)(du/dx)

In our case
y=arcsin(u)
u=sin(x)

dy/du=1/√(1-u²) = 1/√(1-sin²x)
du/dx=cos x

dy/dx=cos x /√(1-sin²x)

Answer: dy/dx=cos x /√(1-sin²x)
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2 years ago
Isi drilled a hole that is 5/9 inch wide.she has a screw that is 5/6 inch wide.is the hole wide enough to fit the screw
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NO the screw is to big to fit

The variable in non simplified form will be

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4 0
3 years ago
SOLVE: 1/2 x 1/5 = *
olga2289 [7]

Answer:

\frac{1}{10}

4 0
3 years ago
Read 2 more answers
I need to do this problem by completing the square . help please
sukhopar [10]

Answer:

the roots are n = 1 + √15 and n = 1 - √15

Step-by-step explanation:

In this case I would immediately rewrite n² - 2n - 5 = 10 as

n² - 2n                  = 10 + 5 = 15.

To complete the square:  Identify the coefficient of n (it is -2). Halve that, obtaining -1, square this result, and then add the outcome (1) to and subtract the outcome (1) to n² - 2n:

n² - 2n  <em>+ 1 - 1   </em>             = 15

Next, rewrite n² - 2n  + 1 as the square of a binomial:

(n - 1)² = 15

Finally, take the square root of both sides:

n - 1 = ±√15

so that the roots are n = 1 + √15 and n = 1 - √15

8 0
3 years ago
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