Im not sure about B. but if you can choose mutiple pick C,D,E but if you can shoose only one than pick A
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let's say they catch-up to each other after t hour.
so
in t hour distance travelled by Renee
d = speed × time = 50t
in t hour distance travelled by Kim
d = speed × time = 60(t-1) + 0×1 = 60(t-1)
Note: here kim didn't covered any distance in first hour and in rest t-1 hour it travelled all distance
now.as distance travelled by both is same so
60(t-1) = 50t
60t -60 = 50t
adding 60 both sides
60t = 50t+60
subtracting 50t both sides
60t -50t = 50t+60 - 50t
10t = 60
dividing by 10 both sides
t = 60/10 = 6
so in 6 hour both will catch-up to each other
Answer:
Telecommunications are the means of electronic transmission of information over distances. The information may be in the form of voice telephone calls, data, text, images, or video. Today, telecommunications are used to organize more or less remote computer systems into telecommunications networks.
Explanation:
Answer:
Explanation:
The code for the given problem is written below
.data
A : .word 1 2 3 4 5 6 7 8 9 10
.text
la $s5,A
li $s1,0 # load g
li $s2,10 # load h
li $s3,0 # load i
li $s4,1 # load j
loop:
mul $s6,$s3,4
add $s6,$s6,$s5 #address of A[i]
lw $s6,($s6) #get value of A[i] in s3
add $s1,$s1,$s6 #g = g+A[i]
add $s3,$s3,$s4 # i = i+j
bne $s3,$s2,loop #if i!=h jump to loop