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Bad White [126]
3 years ago
9

At the frequency of 2.4 GHz what is the free-space path loss in dB.

Computers and Technology
1 answer:
chubhunter [2.5K]3 years ago
6 0

Answer:

The FSBL is 100.05 dB

Solution:

As per the question:

Frequency, f = 2.4 GHz = 2.4\times 10^{9}

Now, we know that to calculate FSBL, i.e., Free Space Path Loss in dB, we use:

FSBL(in dB) = 10log_{10}(\frac{4\pifd}{c})^{2}

where

d = 1 km = 1000

c = 3\times 10^{8} m/s

FSBL(in dB) = 20log_{10}\frac{4\pifd}{c} = 20log_{10}(fd) + 20log_{10}(\frac{4\pi}{c})

FSBL(in dB) = 20log_{10}(f) + 20log_{10}(d) + 20log_{10}(\frac{4\pi}{c})

FSBL(in dB) = 20log_{10}(2.4\times 10^{9}) + 20log_{10}(10^{3}) + 20log_{10}(\frac{4\pi}{3\times 10^{8}})

FSBL(in dB) = 20\times 9.3802 + 20\times 3 - 147.55 = 100.05 dB

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Answer:

D. called

Explanation:

A function is executed when it is called.

Function definition comprises of the code body of the function.For example:

int add(int a, int b){

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}

Function declaration or function prototype specifies the signature of the function ( number and type of arguments, return type). e.g,

int add(int a,int b);

Function call is when the function is executed with actual arguments:

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This will return 6 upon execution of function body.

6 0
3 years ago
PLEASE HELP!
lawyer [7]

To block link that keeps popping up everywhere, one can:

  • Use your browser and click on block Pop-ups  in settings
  • Install an antivirus.

<h3>How do I stop pop-up links?</h3>

One can do so if they Manage the pop-up by blocking it in the Chrome browser where they:

  • Click on Settings from the Chrome menu.
  • input 'pop' in the search bar.
  • Select Site Settings  and then select Pop-ups and redirects.
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Therefore, To block link that keeps popping up everywhere, one can:

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Learn more about pop up link from

brainly.com/question/13666301

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4 0
2 years ago
Given two ArrayLists of sorted strings (alphabetically ascending), write down a method to merge these sorted strings’ ArrayLists
Elena-2011 [213]

Answer:

see explaination

Explanation:

import java.util.ArrayList;

import java.util.Arrays;

public class Merge {

public static ArrayList<String> mergeList(ArrayList<String> lst1, ArrayList<String> lst2) {

ArrayList<String> result = new ArrayList<String>();

int i = 0, j = 0;

while (i < lst1.size() || j < lst2.size()) {

if (i < lst1.size() && (j >= lst2.size() || lst1.get(i).compareTo(lst2.get(j)) < 0)) {

result.add(lst1.get(i++));

} else {

result.add(lst2.get(j++));

}

}

return result;

}

public static void main(String[] args) {

ArrayList<String> lst1 = new ArrayList<>(Arrays.asList("Austin", "Dallas", "San Fransisco"));

ArrayList<String> lst2 = new ArrayList<>(Arrays.asList("Boston", "Chicago", "Denver", "Seattle"));

System.out.println(mergeList(lst1, lst2));

}

}

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