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Anon25 [30]
3 years ago
13

Write a Java method to delete a record from a B-tree of order n.

Computers and Technology
1 answer:
max2010maxim [7]3 years ago
6 0

Answer:

Deleting a record on a B-tree consists of three main events:

- Searching the node where the key to be deleted exists

- Deleting the key

- Balancing the tree if required

Explanation:

q = NULL;

   p = tree;

   while (p) {

       i = nodesearch(p, key);

       q = p;

       if (i < used(p) -1 && key == k(p,i)) {

           found = TRUE;

           position = i;

           break;

       }

       p = son(p,i);

   }

   if (!found)

   else if (subtree(p)) {

         if (used(p) > ((n-1)/2)+1)

         delkey (p, position, key);

       else {

           replace (p, position, fsucc(p));

           p0 r1 p1 r2 p2 r3 ……. pn-1 rn-1 pn

           q = &fsucc(p);

           qpos = index of fsucc;

           if (used(rbrother(p)) > ((n-1)/2)+1)

               replace (q, qpos, sonsucc(q));

           else

               while (q && used(q) < (n-1)/2) {

                   concatenate(q, brother(q));

                   q = father(q);

               }

       }

   }

   else

   delkey(p, position, key);

}

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jekas [21]
The code of five digits is of the form:

A B C D F

Where A (the first digit)  may be any of 9 digits (because 0 is excluded)

B, C, and D, may be each any of 10 digits (0 - 9)


F (the last digit) may be 0, 2, 4, 6 or 8, i.e. 5 different digits.


So the number of different available codes is:

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Answer: 45,000
4 0
3 years ago
The find_item functions uses binary search to recursively locate an item is the list, returning true if found, false otherwise.
bagirrra123 [75]

Answer:

def find_item(listed, item):

   listed.sort()

   #Returns True if the item is in the list, False if not.

   if len(listed) == 0:

       return False

   middle = int(len(listed)/2)

   #Is the item in the first half of the list?

   if item < listed[middle]:

   #Call the function with the first half of the list

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   #Is the item in the center of the list?

   if listed[middle] == item:

       return True

   else:

   #Call the function with the second half of the list

       return find_item(listed[middle+1:], item)

   return False

list_of_names = ["Parker", "Drew", "Cameron", "Logan", "Alex", "Chris", "Terry", "Jamie", "Jordan", "Taylor"]

print(find_item(list_of_names, "Alex")) # True

print(find_item(list_of_names, "Andrew")) # False

print(find_item(list_of_names, "Drew")) # True

print(find_item(list_of_names, "Jared")) # False

Explanation:

The defined python function is used to implement a binary search, the function is recursively called in the function statement, but for it to work on the list ( ie, search for an item in the list), the list must be sorted in ascending order (default).

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AnnyKZ [126]
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alexandr1967 [171]

Answer:

B

Explanation:

The metadata is only the information in the background aka the info not directly given.

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