1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna [14]
3 years ago
10

3/4 (x-12)=12 And 3/4y-12=12

Mathematics
2 answers:
lianna [129]3 years ago
5 0
3/4 (x-12)=12
3/4x - 9= 12
        +9    +9
3/4x=21
*3/4     *3/4
x= 15 3/4

and 

3/4y-12=12
       +12  +12
3/4y = 24
*3/4    *3/4
y= 18
Ket [755]3 years ago
4 0
Oops. I did it wrong. delete.
You might be interested in
Which expressions are equivalent to 4d+6+2d4d+6+2d ? Choose all answers that apply: Choose all answers that apply: (Choice A) A
Sliva [168]

Answer:

Options A and C are correct choices.

Step-by-step explanation:

We have been given an expression 4d+6+2d and we are asked to choose all the equivalent expressions from given choices.

Let us simplify our given expression.

4d+6+2d=(4d+2d)+6

4d+6+2d=6d+6

Let us see which of our given choices matches with our answer.

A. 2(3d+3)

Upon using distributive property a(b+c)=a*b+a*c we will get,

2*3d+2*3

6d+6

Therefore, option A is a correct choice.

B. 6(d+6)

Upon using distributive property a(b+c)=a*b+a*c we will get,

6*d+6*6

6d+36

Since this expression is not equivalent to our answer, therefore, option B is not a correct choice.

C. (3d+3)+(3d+3)

Upon removing parenthesis we will get,

3d+3+3d+3

Upon combining like terms we will get,

(3d+3d)+(3+3)

6d+6

Therefore, option C is the correct choice.

7 0
3 years ago
How to solve this: <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B5%7D%20%20%2B%208" id="TexFormula1" title=" \frac{x
bogdanovich [222]

Answer:

You can't solve it , the equation has to equal something

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
-x=-y+2 and 3y+4=2x solve using matrices
MissTica

\begin{cases}-x=-y+2\\3y+4=2x\end{cases}\implies\begin{cases}x-y=-2\\2x-3y=4\end{cases}

In matrix form, this is

\begin{bmatrix}1&-1\\2&-3\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-2\\4\end{bmatrix}

The coefficient matrix has determinant

\begin{vmatrix}1&-1\\2&-3\end{vmatrix}=-3+2=-1\neq0

so it has an inverse, which is

\begin{bmatrix}1&-1\\2&-3\end{bmatrix}^{-1}=\begin{bmatrix}3&-1\\2&-1\end{bmatrix}

Multiply both sides by the inverse matrix:

\begin{bmatrix}3&-1\\2&-1\end{bmatrix}\begin{bmatrix}1&-1\\2&-3\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}3&-1\\2&-1\end{bmatrix}\begin{bmatrix}-2\\4\end{bmatrix}

\implies\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-10\\-8\end{bmatrix}

so that x=-10 and y=-8.

8 0
4 years ago
(xy)^2 &lt;----this is the promblem......<br><br> WHAT IS THIS IN WORD FORM?
Gnom [1K]
Wouldnt this be something like x and y squared
5 0
3 years ago
Create an equation from the following statement<br> of 15% of 24
Murljashka [212]
15 percent of 24
(15/100) * 24
3.6
4 0
2 years ago
Other questions:
  • In an aquarium, there are 6 large fish and 8 small fish. Half of the large fish are blue.
    14·2 answers
  • A student runs 100 meters in 11 seconds. What is the speed of the student?
    7·1 answer
  • Solving a System of Linear Equations - Applications - Item 92238
    10·1 answer
  • What is the answer 613 + 6y =xy=8.6
    14·1 answer
  • Jayvon drives his boat at a constant speed, described by the question d=25t, where d represents the distance, in miles, that the
    10·1 answer
  • Solve for the value of x.
    8·1 answer
  • Please explain #2 for me please!<br> The question deals with proportions.
    9·1 answer
  • Simplify 7(x - 2) - 4x + 9.<br> O A. 3x+7<br> O B. 3x - 5<br> O C. -11X- 11<br> D. -21 x + 49
    13·1 answer
  • PLEASE HELPP IM BEGGING. Which quadrant is point Fin?<br> A) 1<br> B) 11<br> D) IV
    14·2 answers
  • Complete the equation to represent the relationship. Then solve the equation. Drag
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!