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kenny6666 [7]
4 years ago
5

PLEASE!!!!

Chemistry
2 answers:
Ede4ka [16]4 years ago
7 0
The answer the comes closest to being correct would be answer choice D. the problem with it though is that it does not have the correct amout of neurtrons. It is called rubidium 87 therefor there must be 50 neurtrons if there are 37 electrons and protons 87-37=50, 50+37=87.
kolbaska11 [484]4 years ago
3 0

it's d. taking the test and you have a typo. D should be 50 neutrons not 40

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5 0
3 years ago
A 3.8-mol sample of KClO3 was decomposed according to the equation. How many moles of O2 are formed assuming 100% yield?
kari74 [83]

Answer:

5.7 moles of O2

Explanation:

We'll begin by writing the balanced decomposition equation for the reaction. This is illustrated below:

2KClO3 —> 2KCl + 3O2

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Next, we shall determine the number of mole of O2 produced by the reaction of 3.8 moles of KClO3.

Since 100% yield of O2 is obtained, it means that both the actual yield and theoretical yield of O2 are the same. Thus, we can obtain the number of mole of O2 produced as follow:

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Therefore, 3.8 moles of KClO3 will decompose to produce = (3.8 × 3)/2 = 5.7 moles of O2.

Thus, 5.7 moles of O2 were obtained from the reaction.

3 0
3 years ago
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