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3 years ago

Which type of chemical bond involves the exchange of electrons

Chemistry

1 answer:

Alex17521 [72]3 years ago

5 0

Answer:

Ionic or Electrovalent Bonding

Explanation:

There are primarily two categories of bonding between chemical entities. We have; Ionic Bonding and Covalent Bonding.

Ionic bonding or electrovalent bonding is the complete transfer of valence electron(s) between atoms. There is the transfer of electron from typically a metal to a non metal.

Covalent Bonding however involves the sharing of electrons between atoms. Depending on whuch atoms provide the electrons, it can be ordinary covalent oor coordinate covelent bond.

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Find δh°rxn for the reaction ch4(g) + 2o2(g) → co2(g) + 2h2o(l). [δh°f (ch4(g)) = –74.8 kj/mol; δh°f (co2(g)) = –393.5 kj/mol; δ

saveliy_v [14]

398923 is yo answer home slice

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3 years ago

What is the mass of 1.25 mole of zinc

allochka39001 [22]

Answer:

Explanation:

1 mole is equal to 1 moles Zinc, or 65.38 grams.

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3 years ago

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What is the empirical formula? A compound is used to treat iron deficiency in people. It contains 36.76% iron, 21.11% sulfur, an

Mandarinka [93]

Answer: The empirical formula of the compound is $Fe_1S_1O_4$

Explanation:

Empirical formula is defined formula which is simplest integer ratio of number of atoms of different elements present in the compound.

Percentage of iron in a compound = 36.76 %

Percentage of sulfur in a compound = 21.11 %

Percentage of oxygen in a compound = 42.13 %

Consider in 100 g of the compound:

Mass of iron in 100 g of compound = 36.76 g

Mass of iron in 100 g of compound = 21.11 g

Mass of iron in 100 g of compound = 42.13 g

Now calculate the number of moles each element:

Moles of iron= $\frac{36.76 g}{55.84 g/mol}=0.658 mol$

Moles of sulfur= $\frac{21.11 g}{32.06 g/mol}=0.658 mol$

Moles of oxygen= $\frac{42.13 g}{16 g/mol}=2.633 mol$

Divide the moles of each element by the smallest number of moles to calculated the ratio of the elements to each other

For Iron element = $\frac{0.658 mol}{0.658 mol}=1$

For sulfur element = $\frac{0.658 mol}{0.658 mol}=1$

For oxygen element = $\frac{2.633 mol}{0.658 mol}=4.001\approx 4$

So, the empirical formula of the compound is $Fe_1S_1O_4$

4 0

3 years ago

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The half life of iodine-125 is 60 days. What was the initial amount of iodine-125 if you have 4.5 grams after 360 days?

ValentinkaMS [17]

Answer:

288 grams

Explanation:

The amount of any radiative substance left after some time is calculated by

amount left = $x/2^n$

where x is the initial amount of substance

n is the number of half lives

one half live is the time in which amount of substance reduce to half of its initial value.

------------------------------------------------------

amount left = 4.5 grams

half life of iodine-125 = 60 days

total time in which substance reduced to 4.5 grams = 360 days

thus,

number of half life in 60 days = 360/60 = 6

thus, there are period of 6 half lives

in each half life the amount of substance reduces to its previous half

let the initial amount be x grams

using the formula

amount left = $x/2^n$

$4.5 = x/2^6 \\ 4.5 = x/64\\x = 4.5*64 = 288$

Thus, 288 grams was the initial amount of iodine-125

6 0

3 years ago

What is this answer

Dmitry [639]

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3 years ago