5H2O2 + 2KMnO4<span>+ 3H2SO4 = 5O2 + 2MnSO4 + 8H2O + K2SO4
0,145 moles of KMnO4----------in--------1000ml
x moles of KMnO4---------------in------------46ml
x = 0,00667 moles of KMnO4
according to the reaction:
2 moles of KMnO4------------------5 moles of H2O2
0,00667 moles of KMnO4----------------x
x = 0,01668 moles of H2O2
0,01668 moles of H2O2---------in-----------50ml
x moles of H2O2--------------------in----------1000ml
<u>x = 0,334 mol/L H2O2</u></span>
Answer is 13.668! Or in scientific notation it would be .13668 x 10^2
Q = mcΔT
m = 75 g
c = 4.25 J/gram°C
q = 2450 J
q/mc = ΔT
2450/(75 • 4.25) = 7.7°C
The temperature increased by 7.7°C.