It's simple, just divide 45 1/2 by four. A, 11 3/7
She would have to work at least 12 hours.
At Chili’s, she would be paid 11.75x + 33 per week, with x being the number of hours she worked.
At the Cheesecake Factory, Giselle would be paid 14.50x per week, with x being how many hours she worked.
We want to know how many hours Gisele would have to work for her pay at the Cheesecake Factory to be more than her pay at Chili’s
The inequality 11.75x + 33 < 14.50x is what has to be set up to solve the problem. At how many hours will the pay on the left be less than the pay on the right?
11.75x + 33 < 14.50x
33 < 2.75x
12 < x
So Giselle has to work greater 12 hours a week for her to make more money at the Cheesecake Factory.
Total = Principal * e^(rate*years)
where "e" is the mathematical constant 2.71828182828459
Total = 1,600 * e(.046*4)
Total = 1,600 * 2.71828182828459^(.184)
Total = 1,600 *
<span>
<span>
<span>
1.2020158231
</span>
</span>
</span>
Total =
<span>
<span>
<span>
1,923.23</span></span>
</span>
Source:
http://www.1728.org/rate2.htm
Answer:
Hey there!
Let the cost of one uniform be c, so the expression becomes
c+13+11+18
Thus, we have c+42
Hope this helps :)
The answer is the first option.
